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3 years ago

Miguel has 48 coins.of the 48 coins 5/8 are dimes.how many of the coins are dimes

2 answers:

5 0

A simple way you could solve this is by drawing a tape graph.
Draw a long rectangular box.
Cut the box into 8 pieces, seeing as how 5/8 of the coins are dimes.
We have to take 48 and divide it by 8, we get 6, so now we know how many dimes are evenly split into each piece.
Now color in 5 pieces of the tape.
This represents the 5 in 5/8.
Now to find the number of coins, simply multiply 5 by 6, you get the answer of 30.
I hope this helps, if you are confused with any part of my explanation, ask and I will clarify.

deff fn [24]3 years ago

3 0

30 of the coins are dimes

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ivann1987 [24]

Answer:j

Step-by-step explanation:

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4 years ago

(3x-4y)^2-(3x-4y)(3x+4y)

zheka24 [161]

Answer:

$-24xy + 32y^2$

Step-by-step explanation:

Hello!

We can use the special binomial product formulas:

$(a + b)^2 = a^2 + 2ab + b^2$
$(a + b)(a - b) = a^2 - b^2$

<h3>Simplify</h3>

$(3x - 4y)^2 - (3x - 4y)(3x + 4y)$
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The simplified form is $-24xy + 32y^2$

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2 years ago

What is the length of the missing leg? If necessary, round to the nearest tenth.

Marrrta [24]

Answer:

The length of the hypotenuse is 33 yards.

Step-by-step explanation:

We can solve for 'a' using Pythagoras theorem. Let's solve it.

65² = b² + 56²
=> 4225 = b² + 3136
=> b² = 1089
=> b = 33

Hence, the length of the hypotenuse is 33 yards.

Hoped this helped.

$BrainiacUser1357$

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2 years ago

Luna is buying food for a dinner party. She is going to buy 2 key lime pies that cost $8.99 each. Shrimp costs $8.50 a pound. Sh

spin [16.1K]

Answer:

x=45- 2*8.99/8.50

x~3.18

3 lbs of shrimp

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3 years ago

Consider the three points ( 1 , 3 ) , ( 2 , 3 ) and ( 3 , 6 ) . Let ¯ x be the average x-coordinate of these points, and let ¯ y

loris [4]

Answer:

$m=\dfrac{3}{2}$

Step-by-step explanation:

Given points are: ( 1 , 3 ) , ( 2 , 3 ) and ( 3 , 6 )

The average of x-coordinate will be:

$\overline{x} = \dfrac{x_1+x_2+x_3}{\text{number of points}}$

1) Finding $(\overline{x},\overline{y})$

Average of the x coordinates:

$\overline{x} = \dfrac{1+2+3}{3}$

$\overline{x} = 2$

Average of the y coordinates:

similarly for y

$\overline{y} = \dfrac{3+3+6}{3}$

$\overline{y} = 4$

2) Finding the line through $(\overline{x},\overline{y})$ with slope m.

Given a point and a slope, the equation of a line can be found using:

$(y-y_1)=m(x-x_1)$

in our case this will be

$(y-\overline{y})=m(x-\overline{x})$

$(y-4)=m(x-2)$

$y=mx-2m+4$

this is our equation of the line!

3) Find the squared vertical distances between this line and the three points.

So what we up till now is a line, and three points. We need to find how much further away (only in the y direction) each point is from the line.

Distance from point (1,3)

We know that when x=1, y=3 for the point. But we need to find what does y equal when x=1 for the line?

we'll go back to our equation of the line and use x=1.

$y=m(1)-2m+4$

$y=-m+4$

now we know the two points at x=1: (1,3) and (1,-m+4)

to find the vertical distance we'll subtract the y-coordinates of each point.

$d_1=3-(-m+4)$

$d_1=m-1$

finally, as asked, we'll square the distance

$(d_1)^2=(m-1)^2$

Distance from point (2,3)

we'll do the same as above here:

$y=m(2)-2m+4$

$y=4$

vertical distance between the two points: (2,3) and (2,4)

$d_2=3-4$

$d_2=-1$

squaring:

$(d_2)^2=1$

Distance from point (3,6)

$y=m(3)-2m+4$

$y=m+4$

vertical distance between the two points: (3,6) and (3,m+4)

$d_3=6-(m+4)$

$d_3=2-m$

squaring:

$(d_3)^2=(2-m)^2$

3) Add up all the squared distances, we'll call this value R.

$R=(d_1)^2+(d_2)^2+(d_3)^2$

$R=(m-1)^2+4+(2-m)^2$

4) Find the value of m that makes R minimum.

Looking at the equation above, we can tell that R is a function of m:

$R(m)=(m-1)^2+4+(2-m)^2$

you can simplify this if you want to. What we're most concerned with is to find the minimum value of R at some value of m. To do that we'll need to derivate R with respect to m. (this is similar to finding the stationary point of a curve)

$\dfrac{d}{dm}\left(R(m)\right)=\dfrac{d}{dm}\left((m-1)^2+4+(2-m)^2\right)$