STEP
1
:
Pulling out like terms
Pull out like factors :
32 - 2x = -2 • (x - 16)
STEP
2
:
Equations which are never true:
2.1 Solve : -2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:
2.2 Solve : x-16 = 0
Add 16 to both sides of the equation :
x = 16
C or A could be the answer
Answer:
The length is 23 inches and the width is 6 inches.
Step-by-step explanation:
The perimeter for a rectangular shape is represented as:
P = 2L + 2W, where L represents length and W represents width
We can represent the length as:
L = 3W + 5
Substituting this into the perimeter function, we get:
P = 2 (3W + 5) + 2W
Substituting 58 for P, we get:
58 = 2 (3W + 5) + 2W
58 = 6W + 10 + 2W
58 = 8W + 10
58 - 10 = 8W + 10 - 10
48 = 8W
48 / 8 = 8W / 8
6 = W
With 6 being the established value for the width, we can substitute this back into the equation for length:
L = 3W + 5
L = 3(6) + 5
L = 18 + 5
L = 23
To check our work, we can substitute both the width and length into the perimeter equation:
P = 2L + 2W
58 = 2(23) + 2(6)
58 = 46 + 12
58 = 58
Therefore, length is 23 inches and the width is 6 inches.
Let
x--------> the length side of the original square paper
we know that
<u>the area of the original square paper is equal to</u>
<u>the area of the remaining piece of paper is equal to</u>
therefore
<u>the answer is the option </u>
x2 − 2x − 120 = 0
The first is in the form y=Mx+b where m is the slope and b is the y-intercept. Start at 600 on the y-axis and graph with a slope of six. The second is in the same form but the y-intercept is 0, so start at the origin and graph with a slope of 8. The last is in the form y=b+mx, so start at 1300 and graph with a slope of 3. Remember, slope is rise/run or (change in y)/(change in x). Since the domain and range start at 0 these graphs will only be in the first quadrant with an x limit of 650 and a y limit of 1500.
