Ask question

Ask question

All categories

3 years ago

13

in the square, x represents a positive whole number. find the value of x such that the area is equal to half the perimeter of th

e square.

1 answer:

azamat3 years ago

5 0

Hope this helps
so the area is x^2
<span>and the perimeter is 4x </span>
<span>area = (1/2)perimeter </span>
<span>x^2 = 2x </span>
<span>x^2 - 2x = 0 </span>
<span>x(x-2) = 0 </span>
x = 2<span> or x = 0</span>

You might be interested in

PLEASE HELP {It costs 5,700 every one sixth of an hour to build a hotel how many cents does building a hotel cost per second?}

Keith_Richards [23]

One sixth of an hour is 10 minutes.
That means it costs 5,700 every 10 minutes.

Costs 5,700 = 10 minutes

Dive 10 on both sides.

Costs 570 = 1 minute

Lets convert the minute into seconds.

Costs 570 = 60 seconds

Divide both sides by 60.

Costs 9.5 cents = 1 second

Round it off since you can't pay 9.5 cents.

Costs 10 cents = 1 second

This means that every second they pay 10 cents for the hotel. :D

8 0

3 years ago

Suggest five questions for a questionnaire to discover what opinions people in class have about school.

Snezhnost [94]

Answer:

Which activities in the classroom do you enjoy the most? ...

Given a chance, what is one change that you would like to see? ...

Do you have supportive classmates? ...

What motivates you to learn more? ...

Do you think that the school provides you with adequate sports facilities?

How much time do you spend on homework every night?

Which classroom activities do you learn from the most?

What are three things that can improve the class most?

8 0

3 years ago

SOLVING QUADRATIC EQUATIONS BY SQUARE ROOT<br> 9p^2-6=642

Aleksandr [31]

9p^2 - 6 = 642; / + 6 ;
9p^2 = 648; / ÷9 ;
p^2 = 72 ;
p = + $\sqrt{72} or - \sqrt{72}$ ;
Finally, p = +6 $\sqrt{2}$ or p = -6 $\sqrt{2} .$

7 0

3 years ago

Read 2 more answers

In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a

nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

$\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ}$ ;

$\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ}$ ;

$\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q$ .

Also,

$\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P$ in right triangle PBM.

Thus $\rm \angle{P\hat{B}M} = \angle C\hat{M}Q$ .

Additionally $\rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}$ .

Therefore $\rm \triangle PBM \sim \triangle MCQ$ .

$\rm \displaystyle BC = 2\;MC$ for M is the midpoint of segment BC.

$\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC$ .

$\rm \triangle PBM \sim \triangle MCQ$ implies that

$\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3$ .

8 0

3 years ago

Please i need help <br> i dont know how to do this

kondaur [170]

Do what? I can't see a question

3 0

3 years ago

Read 2 more answers