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grandymaker [24]
3 years ago
13

How many 5-letter passwords can be created if no letter can be used twice within the password?

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0
<span>If there are 5 letters used only, then 5! or 5*4*3*2 = 120
If all 26 letters of the alphabet may be used for the code, then:
26*25*24*23*22
</span><span>If you mean letters of the alphabet, and not case sensitive, it's</span><span>26*25*24*23*22
= 7893600</span>
bonufazy [111]3 years ago
5 0
26*25*24*23*22=7893600

or you can use

26!/(26-5)!=7893600
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Hello from MrBillDoesMath!

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