In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
26x3=78
78-x=72
x=6
She needs to buy at least 6 more to have enough for 26 students
Answer
68℅
Explanation
17/25 =
17 ÷ 25 =
0.68 =
0.68 × 100/100 =
0.68 × 100% =
(0.68 × 100)% =
68%;
Hope that this helps you and have a great day :)
Note that the side adjacent to angle XYZ is given (6 cm) and that the hypo is also given (15 cm). Thus, cos XYZ = adj / hyp = 6 cm / 15 cm = 2/5 = 0.4.
XYZ is then arc cos 0.4. Use the arccos function on your calculator to determine XYZ and give XYZ in both degrees and radians.
Answer:
Answer for the question :
A resercher is wondering whehter the drinking habits of adults in a certain region of the country are in the same proportion as the general population of adults. Suppose a recent study stated that the proportion of adults who reported drinking once a week or less in the last month was 0.26. The researcher's null hypothesis for this test is H0: P=0.26 and the alternative hypothesis is Ha; P> 0.26. The researcher collected datat from a random sample of 75 adults in the region of interest.
1- Verify that the normality assumption is satisfied. Describe each separately.
2- To cotinue the study into the drinking habits of adults, the researcher decides to collect datat from adults working in "blue collar" jobs to see whether their drinking habits are in the same proportion as the general public. The null hypothesis for this test is H0: P=0.26 and the alternative hypothesis is Ha: P>0.26. The researcher computer the test statistic to be 1.59. Draw a graph of z distribution, label the test statistic and shade the p-value associated with this test statistic."
is given in the attachment.
Step-by-step explanation: