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igor_vitrenko [27]
3 years ago
6

2) Today, the price of a pack of pens costs $12. In 2000, the same pack of pens only cost $8. What is the percent of change? 3)

In Orlando, Florida the high temperature was 91 degrees on Saturday and on Sunday was 77 degrees. What is the percent of change? 4)Olivia scored 75 points on a math test. On the second math test, she earned 60 points. What is the percent of change?
Mathematics
2 answers:
ANEK [815]3 years ago
8 0

Answer:

2) 50  3) 18.18...  4) 25

Step-by-step explanation:

12 - 8

8

x 100% = 50%

91 - 77

77

x 100% = 18.1818181818%

75 - 60

60

x 100% = 25%

Alex787 [66]3 years ago
5 0

Answer:

2)4 3)20 4)15

Step-by-step explanation:

12 - 8  

91 - 77

75 - 60

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Zina [86]

Answer:

1. x = -4y ---> y = (-1/4)x

slope = -1/4. y-intercept = (0,0)

2. y = -2x + 4

3. y = (1/3)x - 1

Step-by-step explanation:

1. Re-write your equation so that x is on the right and y is on the left:

x = -4y ---> y = (-1/4)x

slope = -1/4. y-intercept = (0,0)

2. y-intercept = (0,4) ----> P1

x-intercrpt = (2,0) ----> P2

slope m = (y2 - y1) / (x2 - x1)

= (0 - 4)/(2 - 0)

= -2

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5 0
3 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

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