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3 years ago

Joséphine noticed that out of 10 e-mails she

Mathematics

2 answers:

Lynna [10]3 years ago

6 0

Answer:

The answer is C

I did the quiz on edge

tangare [24]3 years ago

6 0

Answer:

The answer is 70

Step-by-step explanation:

no cap

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What is the area of the circle if DF=20 in.

crimeas [40]

We know that

DF is the diameter of the circle
so
radius r=DF/2----->20/2-----> r=10 in

area of the circle=pi*r²------> pi*10²-----> 100*pi in²-----> 314 in²

the answer is

100*pi in² or 314 in²

4 0

2 years ago

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Lelu [443]

Answer:

Step-by-step explanation:

my best guess! it is the best!

7 0

2 years ago

Triangle A B C is shown. Angle A B C is a right angle. An altitude is drawn from point B to point D on side A C to form a right

ivann1987 [24]

Answer:

i think its 1.2 not too sure though

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the volume, in cubic inches, of a basketball with a diameter of 9 inches?

nlexa [21]

Answer:

381.70350741116 inches^3

Step-by-step explanation:

4/3 πr^3 = 4/3 x π x 4.5^3 = 381.70 inches ^3

5 0

3 years ago

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

sineoko [7]

ANSWER

The scale factor is
$2.5$

EXPLANATION

The given triangle has vertices,

$A(0,0),B(0,4),\:and\:C(6, 0)$ .

The vertices of the image triangle is,

$A'(0,0),B'(0,10),\:and\:C'(15, 0)$ .

The scale factor is given by

$k = \frac{image \: length}{object \: length}$

So we can use any of the corresponding sides to determine the scale factor,

$k = \frac{|A'B'|}{ |AB|}$

$k = \frac{ |10 - 0| }{ |4 - 0|}$

$k = \frac{ |10| }{ |4 |} = \frac{10}{4} = 2.5$

Or

$k = \frac{|A'C'|}{ |AC|}$

$k = \frac{ |15 - 0| }{ |6 - 0|}$

$k = \frac{ |15| }{ |6|} = \frac{15}{6} = 2.5$

Or

$k=\frac{|B'C'|}{|BC|}$

$k = \frac{\sqrt{(15 - 0)^2+(0-10)^2 }}{\sqrt{(6 - 0)^2+(0-4)^2}}$

$k = \frac{ 5\sqrt{13}}{2\sqrt{13}} = \frac{5}{2} = 2.5$

The correct answer is C

3 0

2 years ago