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4 years ago

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A town tracks the increases and decreases in its population. The population has decreases by 300 residents over the past 5 years

. The same number of residents left each year. What was the change in the town's population each year?

1 answer:

Ksivusya [100]4 years ago

3 0

Answer:

I think the answer would be -60 (as in 60 people left each year)

Step-by-step explanation:

If the population decreased by 300 over 5 years, and the same number of residents left each year, then you would divide 300 by 5, and that gives you 60.

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On a number line what is the distance between −61.5 and -23.4

strojnjashka [21]

In order to find the distance between -61.5 and -23.4 on the number line, you just have to subtract either the greater value to lesser value or lesser value to the greater value. It doesn't matter when you get a negative difference because the distance should be the absolute value of the difference of two points on a number line.
Here's how you should do it.
   (-61.5) - (-23.4) = -61.5 + 23.4 = l-38.1l = 38.1
or
   (-23.4) - (-61.5) = -23.4 + 61.5 = l38.1l = 38.1

As you can see above, I tried to subtract the two numbers in different order, and the result is still the same. Just make sure to get the absolute value of the answer because the distance should always be in positive form.

Therefore, the distance between -61.5 and -23.4 is 38.1

7 0

3 years ago

Find the probability. Enter your answer as a simplified fraction.

Mashcka [7]

Answer:

$\frac{1}{2}$ is your answer

Step-by-step explanation:

To calculate the probability, you first have to find the total things by adding.

13 + 13 = 26

Then, you find the number of purple marbles which is 13. So, 13 is the numerator, and 26 the denominator.

$\frac{13}{26}$

Next, simplify.

$\frac{13}{26} = \frac{1}{2}$

Have a wonderful day!

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3 years ago

URGENT!! ILL GIVE<br> BRAINLIEST! AND 100 POINTS

MatroZZZ [7]

Answer:

perimeter: add p + m + n

area: use (p × m)/2

find missing side: use p^2 + m^2 = n^2

3 0

1 year ago

Prove that 1³+2³+....n³=n²(n+1)²/4. principle of mathematics induction

alex41 [277]

<h3>The Simplified Question:-</h3>

$\sf 1^3+2^3\dots n^3=\dfrac{n^2(n+1)^2}{2}$

$\\ \sf\longmapsto 1^3+2^3+\dots n^3=\left(\dfrac{n(n+1)}{2}\right)^2$

<h3>Solution:-</h3>

Let

$\\ \sf\longmapsto P(n)=1^3+2^3\dots n^3=\left(\dfrac{n(n+1)}{2}\right)^2$

For n=1

$\\ \sf\longmapsto P(1)=\left(\dfrac{1(1+1)}{2}\right)^2$

$\\ \sf\longmapsto P(1)=\left(\dfrac{1(2)}{2}\right)^2$

$\\ \sf\longmapsto P(1)=\left(\dfrac{2}{2}\right)^2$

$\\ \sf\longmapsto P(1)=(1)^2$

$\\ \bf\longmapsto P(1)=1=1^3$

Let k be any positive integer.

$\\ \sf\longmapsto P(k)= 1^3+2^3\dots k^3=\left(\dfrac{k(k+1)}{2}\right)^2$

We have to prove that p(k+1) is true.

consider

$\sf 1^3+2^3\dots k^3+(k+1)^3$

$\\ \sf\longmapsto \left(\dfrac{k(k+1)}{2}\right)^2+(k+1)^3$

$\\ \sf\longmapsto \dfrac{k^2(k+1)^2}{4}+(k+1)^3$

$\\ \sf\longmapsto \dfrac{k^2(k+1)^2+4(k+1)^3}{4}$

$\\ \sf\longmapsto \dfrac{k+1)^2\left\{k^2+4k+4\right\}}{4}$

$\\ \sf\longmapsto \dfrac{(k+1)^2(k+2)^2}{4}$

$\\ \sf\longmapsto \dfrac{(k+1)^2(k+1+1)^2}{4}$

$\\ \sf\longmapsto \left(\dfrac{(k+1)(k+1+1)}{2}\right)^2$

$\\ \sf\longmapsto (1^3+2^3+3^3\dots k^3)+(k+1)^3$

Thus P(k+1) is true whenever P(k) is true.

Hence by the Principal of mathematical induction statement P(n) is true for $\bf n\epsilon N.$

Note:-

We can solve without simplifying the Question .I did it for clear steps and understanding .

<h3>Learn More:-</h3>

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3 years ago

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Help me on this question with a explanation please.

liq [111]

Answer is 50cm, to get the diameter you divide the circumference by pi.

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3 years ago