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monitta
3 years ago
13

If a point M at (3,-2) is reflected over the y=0 line,what would be the coordinates of M?

Mathematics
1 answer:
eduard3 years ago
7 0

Answer: The coordinates of M would be (3,2).

Step-by-step explanation: I don't know how to explain but I'm 100% sure this is the answer. Your welcome :)

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Planes Q and R are parallel. Explain how you know lines a and b are skew.
IrinaVladis [17]
By definition, skew lines are a pair of lines that are not parallel but do not intersect each other either. Hence, the conclusion would be, the lines are non-coplanar. An example would two random lines drawn in the x and y axes in a cartesian plane, respectively.
7 0
3 years ago
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Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.
MrMuchimi
A random variable following a binomial distribution over n trials with success probability p has PMF

f_X(x)=\dbinom nxp^x(1-p)^{n-x}

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1

The mean is given by the expected value of the distribution,

\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}

The remaining sum has a summand which is the PMF of yet another binomial distribution with n-1 trials and the same success probability, so the sum is 1 and you're left with

\mathbb E(x)=np=126\times0.27=34.02

You can similarly derive the variance by computing \mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2, but I'll leave that as an exercise for you. You would find that \mathbb V(X)=np(1-p), so the variance here would be

\mathbb V(X)=125\times0.27\times0.73=24.8346

The standard deviation is just the square root of the variance, which is

\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834
7 0
4 years ago
Two Trends pay the restaurant bill in the ratio of 16:4. If more paying friend pays
Inessa05 [86]

Answer:

Cici O i itcivouvitci cc tfurx

Step-by-step explanation:

vhihciycyivovitcu

8 0
3 years ago
How do I find the volume of this?​
lorasvet [3.4K]

Answer:

(64+320π) cm^3

Step-by-step explanation:

The volume of a cube is the length*width*height, so

the volume of this cube is 4*4*4=64 cm^3

The volume of a cylinder is the base*height

The base of a cylinder is the area of a circle, which is π*the radius of the circle squared

The diameter of the circle base is 16, and the radius is half the diameter, so it is 16/2=8.

The area of the base of the cylinder is π8^2=64π

Now, multiply the base by the height, 5

64π*5=320πcm^3

We now have the volume of the cube and the volume of the cylinder, so now we just add them:

(64+320π) cm^3

7 0
3 years ago
Helpppppp plsssssssss
bekas [8.4K]

Answer:

C

Step-by-step explanation:

The right triangle on the right side of the figure has a height of 6 (two same sides lengths) and a base of 3.

x is the hypotenuse (side opposite of 90 degree angle).

We can use the pythagorean theorem to find x. The pythagorean theorem tells us to square each leg (height and base) of the triangle and add it. It should be equal to the hypotenuse square.

For this triangle it means, we square 6 and 3 and add it. It should be equal to x squared. Then we can solve. Shown below:

6^2 + 3^2 = x^2\\36 + 9 = x^2\\45 = x^2\\x=\sqrt{45}

<em>Now we can use property of radical  \sqrt{x}\sqrt{y}  =\sqrt{x*y}  to simplify:</em>

x=\sqrt{45} \\x=\sqrt{5*9} \\x=\sqrt{5} \sqrt{9} \\x=3\sqrt{5}

Correct answer is C

6 0
3 years ago
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