Let x = width
<span>length is 8 cm more than three times it’s width so length = 3x + 8
</span>
Perimeter of a rectangle = 2(L + W)
so
128 = 2(x + 3x + 8) solve for x (width)
128 = 2(4x + 8)
64 = 4x + 8
4x = 56
x = 14
width = 14 cm
length = 3(14) + 8 = 50 cm
Answer:
width = 14 cm
length = 50 cm
Answer:
attempts are required to find a matching pair if the digital fingerprint is 64 bits long.
attempts are required to find a matching pair if the digital fingerprint is 128 bits long.
Step-by-step explanation:
Each bit has two options. So
How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?
So for each of the 64 bits, we have the following number of options.
2 - 2 - 2 - 2 -... - 2
So, in all, there are
options.
So, attempts are required to find a matching pair if the digital fingerprint is 64 bits long.
128 bits long?
Using the same logic as the first question.
So, attempts are required to find a matching pair if the digital fingerprint is 128 bits long.
The answer to this question is true. Based on my knowledge and research, the deviation is, in fact, the difference between any value and the mean of the entire set.
If all were kids, there would be 20 legs. A horse has 2 more legs than a kid. The extra 10 legs can be attributed to there being 5 horses.
Answer:
8.8
Step-by-step explanation:
kids cheating in tests.....
8.7749643787
8.8(1dp)
