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fenix001 [56]
3 years ago
14

Suppose that the height above ground of a person sitting on a Ferris wheel is described by the following.

Mathematics
1 answer:
sdas [7]3 years ago
8 0

Answer:

Person will be 24 metres above the ground after 1.50 minutes

Step-by-step explanation:

Given:

h(t)=18.8-16.7\cos \left ( \frac{2\pi t}{5} \right )

To find:

time when the person be 24 meters above the ground

Solution:

Put h(t)=24

h(t)=18.8-16.7\cos \left ( \frac{2\pi t}{5} \right )\\24=18.8-16.7\cos \left ( \frac{2\pi t}{5} \right )\\16.7\cos \left ( \frac{2\pi t}{5} \right )=18.8-24\\16.7\cos \left ( \frac{2\pi t}{5} \right )=-5.2\\\cos \left ( \frac{2\pi t}{5} \right )=\frac{-5.2}{16.7}\\\cos \left ( \frac{2\pi t}{5} \right )=-0.3114\\\frac{2\pi t}{5}=1.887\\\frac{2}{5}\times \frac{22}{7}t=1.887\\t=1.887\times \frac{5}{2}\times \frac{7}{22}\\=1.501\\\approx 1.50 \,\,minute

So, the person will be 24 metres above the ground after 1.50 minutes

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For this case we can raise a rule of three based on Anthony trotting 11 \frac {1} {2} miles in 23 minutes.

11 \frac {1} {2} = \frac {2 * 11 + 1} {2} = \frac {23} {2}

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3 years ago
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Answer:

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Step-by-step explanation:

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