Answer: E. (x+5)^2 + (y-5)^2 = 9
Step-by-step explanation:
The equation of a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius.
We are given that the center is (-5,5), which means that h = -5 and k = 5.
We are also given that the radius (r) = 3, which means r^2 = 9.
Therefore, the equation should be (x-(-5))^2 + (y-5)^2 = 9.
--> (x+5)^2 + (y-5)^2 = 9
Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) = 
= 
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4
You would need to come in 583.6 or 584 times
Answer:
32
Step-by-step explanation:
i simplified it
Answer:
0.04444444444
Step-by-step explanation: