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3 years ago

Triangle ABC is located at A (1,3), 8 (4,1) and C (3,4). Perform the following sequence of transformations.

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

5 0

Answer:

A (3,1) B (1,4) C (4,3)

Step-by-step explanation:

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A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago

The area of the triangle below is ? Sq. Units <br> A. 66<br> B . 33<br> C . 50 <br> D . 25

kykrilka [37]

Answer:

The answer is B.

Step-by-step explanation:

You have to apply the area of triangle formula :

$area = \frac{1}{2} \times base \times height$

$let \: base = 22 \\ let \: height = 3$

$area = \frac{1}{2} \times 22 \times 3$

$area = 11 \times 3$

$area = 33 \: {units}^{2}$

6 0

3 years ago

Read 2 more answers

Solve the equation: -6p + 14 and 3p - 2

sleet_krkn [62]

Answer:

p = 16/9

Step-by-step explanation:

$-6p+14=3p-2\qquad\text{subtract 14 from both sides}\\\\-6p=3p-16\qquad\text{subtract 3p from both sides}\\\\-9p=-16\qquad\text{divide both sides by (-9)}\\\\\boxed{p=\dfrac{16}{9}\to p=1\dfrac{7}{9}}$

5 0

3 years ago

SOLVE FOR X. pls i need help

Lyrx [107]

X=8
Set up proportions would give you: 10/3x+1 = 22/7x-1
With that in mind, cross multiply, which would give you: 10(7x-1) = 22(3x+1).
Turns into: 70x -10 = 66x+22. Then just solve for x

5 0

3 years ago

I don’t understand!!!!!

Sergio039 [100]

These are vertical angles, meaning they're always the same length.

$3x = x + 28$

$2x = 28$

$x = 14$

4 0

3 years ago