Make an inequality representing both constraints.
0.5x+y<20
x+y≥24
for a
if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, 
has a slope of -2.
now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.
![\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope = m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5](https://tex.z-dn.net/?f=%20%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B7%7D%29%5Cqquad%20%5Cqquad%20%5Cqquad%20slope%20%3D%20%20m%5Cimplies%20-2%5C%5C%5C%5C%5C%5C%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-7%3D-2%5Bx-%28-1%29%5D%5C%5C%5C%5C%5C%5Cy-7%3D-2%28x%2B1%29%5Cimplies%20y-7%3D-2x-2%5Cimplies%20y%3D-2x%2B5%20)
Answer:
Step-by-step explanation:
AD and EH are parallel lines
Angle CBD = Angle CFH = x (corresponding angles)
x + 2x = 180 (angles on a straight line)
3x = 180
x = 60
Angle GFH = 120
Angle CBD = 60
y = 1 is a horizontal line which has a slope of 0.
A line perpendicular to it, a vertical line, has an undefined slope. A line parallel to it, also a horizontal line, has a slope of 0.
Learn this, it helps..
HOY -- horizontal line, 0 slope, represented by y = a number
VUX -- vertical line, undefined slope, represented by x = a number.
Answer:
C) Yes, because 1 and 5 are congruent
Step-by-step explanation:
Same-side congruent angles prove this to be true
