Using exponential functions, it is found that:
a) Since the <u>amount of caffeine will be less than 50 mg</u>, the patient will be ready for the blood test by 6 a.m.
b) The patient could have ingest 231 milligrams of caffeine.
A decaying <em>exponential function</em> is modeled by:
![A(t) = A(0)(1 - r)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%281%20-%20r%29%5Et)
In which:
- A(0) is the initial value.
- r is the decay rate, as a decimal.
In this problem:
- Caffeine metabolize at a rate of 13% per hour, hence
.
Then:
![A(t) = A(0)(1 - r)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%281%20-%20r%29%5Et)
![A(t) = A(0)(1 - 0.13)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%281%20-%200.13%29%5Et)
![A(t) = A(0)(0.87)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%280.87%29%5Et)
Item a:
The coffee cup contains 150 milligrams of caffeine, hence
.
At 6 a.m., it is 8 hours after drinking the coffee, hence we have to find A(8).
![A(t) = A(0)(0.87)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%280.87%29%5Et)
![A(8) = 150(0.87)^8](https://tex.z-dn.net/?f=A%288%29%20%3D%20150%280.87%29%5E8)
![A(8) = 49.2](https://tex.z-dn.net/?f=A%288%29%20%3D%2049.2)
Since the <u>amount of caffeine will be less than 50 mg</u>, the patient will be ready for the blood test by 6 a.m.
Item b:
This A(0), considering <u>A(11) = 50</u>, hence:
![50 = A(0)(0.87)^{11}](https://tex.z-dn.net/?f=50%20%3D%20A%280%29%280.87%29%5E%7B11%7D)
![A(0) = \frac{50}{(0.87)^{11}}](https://tex.z-dn.net/?f=A%280%29%20%3D%20%5Cfrac%7B50%7D%7B%280.87%29%5E%7B11%7D%7D)
![A(0) = 231](https://tex.z-dn.net/?f=A%280%29%20%3D%20231)
The patient could have ingest 231 milligrams of caffeine.
A similar problem is given at brainly.com/question/25537936