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3 years ago

Dayami works at Future Shop and earns $10.50/h plus 6% commission on sales. Last

Mathematics

1 answer:

skad [1K]3 years ago

7 0

<h2>Quick answer :</h2>

$= \tt\$570$

<h2>Answer with steps :</h2>

Money Dayami earns for an hour's work = $10.50

Number of hours Dayami worked last week = 40

Money Dayami would have gotten for her work :

$=\tt 10.50 \times 40$

$=\tt \$ \: 420$

Thus, money earned by Dayami for her work = $420

Total sales Dayami made last week = $2050

Money Dayami must have earned as commission :

= 6% of total sales

$= \tt6 \% \: of \: 2500$

$= \tt\frac{6}{100} \times 2500$

$=\tt \frac{15000}{100}$

$=\tt \$150$

Thus, money Dayami earned as a commission = $150

Dayami's weekly gross salary last week :

$= \tt420 + 150$

$=\color{plum} \tt \: \$570$

Thus, total salary = $570

Therefore, Dayami's gross salary last week = $570

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We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.

A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.

Let $\mu$ = true mean speed of the vehicles.

SO, Null Hypothesis, $H_0$ : $\mu \leq$ 30 miles per hour {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}

Alternate Hypothesis, $H_A$ : $\mu$ > 30 miles per hour {means that the mean speed of vehicles is greater than 30 miles per hour}

The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean speed of 15 vehicles = 31 mph

s = sample standard deviation = 4.7 mph

n = sample of vehicles = 15

So, test statistics = $\frac{31-30}{\frac{4.7}{\sqrt{15} } }$ ~ $t_1_4$

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Hence, the value of test statistics is 0.824.

Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.

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