Answer:
This is not a good solution
Explanation:
Your web browser uses port 80 outgoing to make web requests, so if you’re blocking incoming port 80, all you’re blocking is users of the organization from connecting to the internet. You have indeed close a vulnerable port to access from hackers, but this also can reduce the productivity of the organization.
Answer:
A = 120
B = 40
C = 70
Solution:
As per the question:
Manufacturer forced to make 10 more type C clamps than the total of A and b:
10 + A + B = C (1)
Also, 3 times as many type B as type A clamps are:
A = 3B (2)
The total no. of clamps produced per day:
A + B + C = 330 (3)
The no. of each type manufactured per day:
Now, from eqn (1), and (3):
A + B + 10 + A + B = 330
2A + 2B = 320
A + B = 160 (4)
Now, from eqn (2) and (4):
3B + B = 160
B = 40
Since, A = 3B
A = 
A = 120
Put the values of A and C in eqn (3):
120 + 40 + C = 330
C = 70
Answer:
Digital formats allow for lossless data storage, fast editing (without the loss of original source material, ie having to manually clip pieces of film), and made collaboration easier.
Answer:
12. for (i = 0 ; i < testGrades.length ; i+=1 ){
13. if (testGrades[i] > 100){
14. sumExtra = sumExtra + testGrades[i] - 100;}
15. }
Explanation:
We first iterate through the entire testGrades array. For each test score that is in testGrades ( that is testGrades[i] ), we see whether or not the test grade is above 100 (See line 12) . If test grade is greater than 100, this means we have extra credit. We simply subtract 100 from the test grade, add it with the previous value of sumExtra and store the value back in sumExtra(see line 14). Once i is greater than the length of the test grades, the loop is exited. We can now print sumExtra to obtain the result.
Answer:
By thinking of ways to create environment friendly products such as biodegradable water bottles
