I haven’t read it, but just by the title it was probably talking about an incredible machine that was new to people.
Answer:
- equation = input("Enter an equation: ")
-
- if("+" in equation):
- operands = equation.split("+")
- result = int(operands [0]) + int(operands[1])
- print(operands[0] + "+" + operands[1] + "=" + str(result))
- elif("-" in equation):
- operands = equation.split("-")
- result= int(operands [0]) - int(operands[1])
- print(operands[0] + "-" + operands[1] + "=" + str(result))
- elif("*" in equation):
- operands = equation.split("*")
- result = int(operands [0]) * int(operands[1])
- print(operands[0] + "*" + operands[1] + "=" + str(result))
- elif("/" in equation):
- operands = equation.split("/")
- result = int(operands [0]) / int(operands[1])
- print(operands[0] + "/" + operands[1] + "=" + str(result))
- elif("%" in equation):
- operands = equation.split("%")
- result = int(operands [0]) % int(operands[1])
- print(operands[0] + "%" + operands[1] + "=" + str(result))
Explanation:
The solution code is written in Python 3.
Firstly prompt user to enter an equation using input function (Line 1).
Create if-else if statements to check if operator "+", "-", "*", "/" and "%" exist in the input equation. If "+" is found (Line 3), use split method to get the individual operands from the equation by using "+" as separator (Line 5). Output the equation as required by the question using string concatenation method (Line 6). The similar process is repeated for the rest of else if blocks (Line 7 - 22).
.The answer is <span>sans serif. </span>Utilize sans serif textual styles in light of the fact that the close uniform width of the strokes keeps the text style intelligible when lessened in determination or diminished in text dimension. Sans serif textual styles are more clear from more distant away, which is the reason they are useful for blurbs and slides, especially the titles and headers.
B. It is a code that creates multiple copies on loading and damages the system