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nydimaria [60]
4 years ago
9

How many grams of ice at 0c could be melted by the additional of 0.400 kJ of heat

Chemistry
1 answer:
enot [183]4 years ago
3 0
To solve this we will use the formula q=mc delta T. Q is heat, m is mass, c is specific heat and delta T is change in temperature. because it is a phase change problem, temperature does not apply. Also, we will use heat of fusion of water (344J/g) instead of specific heat. We will also convert 0.400 kJ to J, which becomes 400 J.

0<span>.400 kJ x (1000 J/1 kJ) = 400 J </span>

<span>400 J = (g) x (334 J/g) </span>

<span>g = 1.198 

Because of sig figs, we will round to 1.20 grams (3 sig figs). The answer is 1.20 grams.</span>
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<h3>What is an ideal gas?</h3>

An Ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

Assuming the gas is ideal, we can solve this problem by using the following equation:

PV = nRT

Where:

P = 825 torr ⇒ 825 / 760 = 1.08 atm

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n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

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We input the data:

1.08 atm x 50 L = n x 0.082 atm·L·mol⁻¹·K⁻¹ x 295.16 K

And solve for n:

24.20312

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Hence, 2.2311 moles of gas are there in a 50. 0 L container at 22. 0 °c and 825 torrs.

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