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2 years ago

How many moles of gas are there in a 50. 0 l container at 22. 0 °c and 825 torr?

Chemistry

1 answer:

andre [41]2 years ago

5 0

2.2311 moles of gas are there in a 50. 0 l container at 22. 0 °c and 825 torrs.

<h3>What is an ideal gas?</h3>

An Ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

Assuming the gas is ideal, we can solve this problem by using the following equation:

PV = nRT

Where:

P = 825 torr ⇒ 825 / 760 = 1.08 atm

V = 50 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 22 °C ⇒ 22 + 273.16 = 295.16 K

We input the data:

1.08 atm x 50 L = n x 0.082 atm·L·mol⁻¹·K⁻¹ x 295.16 K

And solve for n:

24.20312

n = 2.2311 mol

Hence, 2.2311 moles of gas are there in a 50. 0 L container at 22. 0 °c and 825 torrs.

Learn more about ideal gas here:

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3 years ago

A 4.24 kg marble slab has the volume of 1564 cm3 What is the density in g/cm3

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3 years ago

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3 years ago

A 1.87 L aqueous solution of KOH contains 155 g of KOH . The solution has a density of 1.29 g/mL . Calculate the molarity ( M ),

Semenov [28]

Answer:

[KOH] : 1.47 M

[KOH] : 1.22 m

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Explanation:

First of all we must determine the volume of solution. We have to work with the density

Density = mass / volume

1.29 g/ml = mass / 1870 ml

1.29 g/ml . 1870 ml = 2412.3

Now we must convert the mass to moles

155g / 56.1 g/ mol = 2.76 moles

Now we can calculate molarity

2.76 mol / 1.87 L = 1.47 M

To calculate molality we have to find out the mass of solvent

mass solute + mass solvent = mass solution

155 g + mass solvent = 2412.3 g

2412.3g - 155g = 2257.3g

We have to convert the 2257.3 g to kg

2257.3 g = 2.25 kg

molality = 2.76 moles / 2.25 kg = 1.22 m

To find out the % mass percentation, we have to calculate the mass of solute in 100 g of solution.

In 2412.3 g of solution we have 155 g of KOH

In 100 g of solution, we would have (100 . 155) / 2412.3 = 6.42 %mass percent.

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