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Cerrena [4.2K]
3 years ago
6

There were two trees growing from seeds in a backyard. One tree grew at a rate of 1//2 of a foot every 2 years. The other grew 4

inches every 3 years. In 12 years, what will the difference between the heights of the two trees be in inches?? Plzz I will give you 299 points
Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer:

The height between the two trees will be 1.67 feet.

Step-by-step explanation:

What you do is you take the 1/2 have and times it by 6 because it is every two years that the tree grows 1/2 of a foot. So it will be 3 feet. The other tree grew 4 inches in 3 years so it will be 16 inches you will then have to make the 16 inches into feet to get 1 1/3. You will then minus the 3 feet and the 1 1/3 to get 5/3 or 1.67 feet.

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3 years ago
In the figure below, B is between A and C, and C is between B and D. If AC=9, BD=10, and BC-2, find AD
ehidna [41]

Considering the situation described in the problem, the length of segment AD is of: 17 units.

<h3>How to find the length of segment AD?</h3>

From the situation described in the problem, segment AD is divided into three parts:

  • Part AB.
  • Part BC.
  • Part CD.

Then, the length of segment AD is:

AD = AB + BC + CD.

We have that AC = 9, hence:

AB + BC = 9.

We also have that BD = 10, then:

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Since BC = 2, we have that:

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Then the length of segment AD is given as follows:

AD = AB + BC + CD = 7 + 2 + 8 = 17.

More can be learned about the length of segments at brainly.com/question/7694028

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HeLp Me pLeAsE?
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