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katen-ka-za [31]
3 years ago
10

Given the function f(x) = The quantity of 2x minus 5, divided by 3 , which of the below expressions is correct? (1 point) f−1(x)

= The quantity of 5 minus 2x, divided by 3. f−1(x) = The quantity of 3x minus 5, divided by 2. f−1(x) = The quantity of 3x plus 5, divided by 2. f−1(x) = The quantity of negative 2x minus 5, divided by 3.
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

f^{-1}(x)=the quantity of 3x plus 5 divided by 2

Step-by-step explanation:

We are given that a function f(x)=\frac{2x-5}{3}

We have to find the correct expression

Suppose y=\frac{2x-5}{3}

3y=2x-5

3y+5=2x

x=\frac{3y+5}{2}

Therefore, f^{-1}(x)=\frac{3x+5}{2}

Answer:f^{-1}(x)=the quantity of 3x plus 5 divided by 2

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The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det
Maru [420]

Answer:

0.077994

Step-by-step explanation:

Given that the owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club.

H_0: Mean = 30\\H_a: Mean >30

(Right tailed test)

Sample size = n=250

Sample mean = 30.45

Mean difference =30.45-30=0.45\\

Sample std dev s = 5

Sample std error = \frac{5}{\sqrt{n} } =\frac{5}{\sqrt{250} } \\=0.3163

Test statistic = Mean diff/std error = =\frac{0.45}{0.3163} =1.423

Since population std deviation is not know we use t test

p value = 0.077994

4 0
3 years ago
How many ways are there to divide 4 men and 4 women into two groups of size 4 each?
Arisa [49]
You have 8 people, you have 2 groups of 4.

8!/4!4!
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=(8*7*6*5)/(4*3*2)
=7*6*5/3
=7*2*5
=70

It's been a few years since I've done this. If you haven't learned how to do this type of an equation yet, then I'm probably wrong.
4 0
2 years ago
Ray BD bisects ABC so that m 2DBC = (x + 6)° and m ZABD = (2x – 12). What is x?
Ludmilka [50]
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5 0
2 years ago
If a positive integer is equal to the following product: 25b3c425b3c4, where b and c are distinct prime numbers greater than 2,
Vlad [161]

Answer: 64 distinct even factors

Step-by-step explanation:

let the 2 distinct numbers be b and c and the integer is expected to be 25b3c425b3c4

since b, c > 2 and prime numbers,

potential options include 3, 5, and 7

hence the likelihoods are (b = 3, c = 5), (b = 5, c = 3), (b = 3, c = 7), (b = 7, c = 3), (b = 5, c = 7), (b = 7, c = 5)

Possibility 1 (b = 3, c = 5)

integer is now 253354253354

the distinct even factors = 2, 202, 262, 1934, 19802, 26462, 195334, 253354, 2000002, 2594062, 19148534, 25588754, 262000262, 1934001934, 2508457954, 253354253354

number of distinct even factors = 16

Possibility 2 (b = 5, c = 3)

integer is now 255334255334

the distinct even factors = 2, 86, 202, 5938, 8686, 19802, 253354, 599738, 851486, 2000002, 25788734, 58792138, 25588754, 86000086, 2528061934, 1934001934, 5938005938, 253354253354

number of distinct even factors = 18

Possibility 3 (b = 3, c = 7)

integer is now 253374253374

the distinct even factors = 2, 6, 22, 66, 202, 242, 606, 698, 726, 2094, 2222, 6666, 7678, 19802, 23034, 24442, 59406, 70498, 73326, 84458, 211494, 217822, 253374, 653466, 775478, 2000002, 2326434, 2396042, 6000006, 6910898, 7188126, 8530258, 20732694, 22000022, 25590774, 66000066, 76019878, 228059634, 242000242, 698000698, 726000726, 836218658, 2094002094, 2508655974, 7678007678, 23034023034, 84458084458,253354253354

number of distinct even factors = 48

Possibility 4 (b = 7, c = 3)

integer is now 257334257334

the distinct even factors = 2, 6, 14, 22, 42, 66, 154, 202, 462, 606, 1114, 1414, 2222, 3342, 4242, 6666, 7798, 12254, 15554, 19802, 23394, 36762, 46662, 59406, 85778, 112514, 138614, 217822, 257334, 337542, 415842, 653466, 787598, 1237654, 1524754, 2000002, 2362794, 3712962, 4574262, 6000006, 8663578, 11029714, 14000014, 22000022, 25990734, 33089142, 42000042, 66000066, 77207998, 121326854, 154000154, 231623994, 363980562, 462000462, 849287978, 1114001114, 2547863934, 3342003342, 7798007798, 12254012254, 23394023394, 36762036762, 85778085778, 257334257334

number of distinct even factors = 64

Possibility 5 (b = 5, c = 7)

integer is now 255374255374

the distinct even factors = 2, 14, 34, 58, 74, 202, 238, 406, 518, 986, 1258, 1414, 2146, 3434, 5858, 6902, 7474, 8806, 15022, 19802, 24038, 36482, 41006, 52318, 99586, 127058, 138614, 216746, 255374, 336634, 574258, 697102, 732674, 889406, 1517222, 2000002, 2356438, 3684682, 4019806, 5128718, 9762386, 12455458, 14000014, 21247546, 25792774, 34000034, 58000058, 68336702, 74000074, 87188206, 148732822, 238000238, 361208282, 406000406, 518000518, 986000986, 1258001258, 2146002146, 2528457974, 6902006902, 8806008806, 15022015022, 36482036482, 255374255374

number of distinct even factors = 64

Possibility 6 (b = 7, c = 5)

integer is now 257354257354

the distinct even factors = 2, 202, 19802, 257354, 2000002, 25992754, 2548061954, 257354257354

number of distinct even factors = 8

From the six possibilities, the highest number of likely distinct even factors is 64

7 0
3 years ago
How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
Scorpion4ik [409]

Answer:

x=4/3y

The grapgh is below

Hope This Helps!!!

8 0
2 years ago
Read 2 more answers
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