The confidence interval is from 0.2191 to 0.2649, given by
![0.242\pm0.0229](https://tex.z-dn.net/?f=0.242%5Cpm0.0229)
.
The z-score we need is found by first subtracting the confidence level from 1:
1 - 0.95 = 0.05
Divide that by 2:
0.05/2 = 0.025
Subtract that from 1:
1 - 0.025 = 0.975
Look this up in the middle of a z-table (http://www.z-table.com) and we see that the z-score is 1.96.
Now our confidence interval is given by
Answer:
Hans has done a mistake in the second step.
The correct answer is:
5x^2+13x-6=0
5x^2+15x-2x-6x=0 - 5. -6=-30 -30=15. -2
5x(1+3x)-2x(1+3x)=0
(5x-2x)(1+3x)=0
5-2x=0 1+3x=0
x=5/2 x=-1/3
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.
Explanation:
A) The probability that it is brown is the percentage of brown we have. Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%. The probability that one drawn is yellow or blue would be the two percentages added together: 15+20 = 35%. The probability that it is not green would be the percentage of green subtracted from 100: 100-5=95%. Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events. All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.
The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:
0.85^3 = 0.614 = 61.4%.
The probability that at least one is green is computed by subtracting 1-(probability of no green). We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
Answer:
40 square units
Step-by-step explanation:
First of all, lets say that square has side
, so, the area unit is ![l^2](https://tex.z-dn.net/?f=l%5E2)
the diagonal's square is ![l\sqrt{2}](https://tex.z-dn.net/?f=l%5Csqrt%7B2%7D)
CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)
![A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2](https://tex.z-dn.net/?f=A_%7Btriangles%7D%3D4%2Abase%2Aheigh%2A0.5%3D2%2A%28l%5Csqrt%7B2%7D%20%29%282l%5Csqrt%7B2%7D%20%29%3D8l%5E2)
CALCULATION OF MAIN SQUARE AREA
![A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2](https://tex.z-dn.net/?f=A_%7Bsquare%7D%3Dside%2Aside%3D%284%5Csqrt%7B2%7D%20l%29%284%5Csqrt%7B2%7D%20l%29%3D32l%5E2)
TOTAL AREA
![A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2](https://tex.z-dn.net/?f=A_%7Btotal%7D%3DA_%7Btriangles%7D%2BA_%7Bsquare%7D%3D8l%5E2%2B32l%5E2%3D40l%5E2)
Step-by-step explanation:
A=base length × height
if base is 6cm, and h 4 cm, multiply
6×4=24cm2