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jeyben [28]
3 years ago
6

Suppose you could climb to the top of the Great Pyramid of Giza in Egypt. Which path would be shorter, climbing a lateral edge o

r the slant height? Justify your response.

Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0
Check the picture below.

if you go from the slant height, the path is shorter to the top, since the hypotenuse is the longest of all sides in a right-triangle.

that said, is shorter but is also steeper, so the lateral edge is longer but less steep and thus a bit simpler though longer, but we're only asked on which is shorter.

You might be interested in
Match each set of points with the quadratic function whose graph passes through those points.
AnnZ [28]

Answer:

f(x) = x² - 2x - 15 passes through (-3 , 0) , (0 , -15) , (5 , 0)

f(x) = -x² - 2x + 15 passes through (-2 , 15) , (-1 , 16) , (0 , 15)

f(x) = -x² + 2x - 15 passes through (0 , -15) , (1 , -14) , (2 , -15)

Step-by-step explanation:

* Lets explain how to solve this question

- To find the points whose graph passes through them substitute the

  x-coordinate in the function if the answer is the same with the

  y-coordinate of the point then the graph passes through this point

  lets do that

- Check the first set of points with the first function

# Pint (0 , -15)

∵ f(x) = x² - 2x - 15

∴ f(0) = (0)² - 2(0) - 15 = -15 ⇒ same value of y-coordinate

∴ The graph of the function passes through point (0 , -15)

# Pint (1 , -14)

∵ f(x) = x² - 2x - 15

∴ f(0) = (1)² - 2(1) - 15 = -16 ⇒ not same value of y-coordinate

∴ The graph of the function does not pass through point (1 , -14)

∴ The graph does not pass through this set of points

- Check the second set of points with the first function

# Pint (-2 , 15)

∵ f(x) = x² - 2x - 15

∴ f(0) = (-2)² - 2(-2) - 15 = 4 + 4 - 15 -7 ⇒ not same value of y-coordinate

∴ The graph of the function does not pass through point (-2 , 15)

∴ The graph does not pass through this set of points

- Check the third set of points with the first function

# Pint (-3 , 0)

∵ f(x) = x² + 2x - 15

∴ f(0) = (-3)² - 2(-3) - 15 = 9 + 6  -15 = 0 ⇒ same value of y-coordinate

∴ The graph of the function passes through point (-3 , 0)

# Pint (0 , -15)

∵ f(x) = x² - 2x - 15

∴ f(0) = (0)² - 2(0) - 15 = -15 ⇒ same value of y-coordinate

∴ The graph of the function passes through point (0 , -15)

# Pint (5 , 0)

∵ f(x) = x² + 2x - 15

∴ f(0) = (5)² - 2(5) - 15 = 25 - 10  -15 = 0 ⇒ same value of y-coordinate

∴ The graph of the function passes through point (5 , 0)

∴ The graph passes through this set of points

* f(x) = x² - 2x - 15 passes through (-3 , 0) , (0 , -15) , (5 , 0)

- Check the first set of points with the second function

# Pint (0 , -15)

∵ f(x) = -x² - 2x + 15

∴ f(0) = -(0)² - 2(0) + 15 = 15 ⇒ not same value of y-coordinate

∴ The graph of the function does not passes through point (0 , -15)

∴ The graph does not pass through this set of points

- Check the second set of points with the second function

# Pint (-2 , 15)

∵ f(x) = -x² - 2x + 15

∴ f(0) = -(-2)² - 2(-2) + 15 = -4 + 4 + 15 = 15 ⇒ same value of y-coordinate

∴ The graph of the function passes through point (-2 , 15)

# Pint (-1 , 16)

∵ f(x) = -x² - 2x + 15

∴ f(0) = -(-1)² - 2(-1) + 15 = -1 + 2 + 15 = 16 ⇒ same value of y-coordinate

∴ The graph of the function passes through point (-1 , 16)

# Pint (0 , 15)

∵ f(x) = -x² - 2x + 15

∴ f(0) = -(0)² - 2(0) + 15 = 15 ⇒ same value of y-coordinate

∴ The graph of the function passes through point (0 , 15)

∴ The graph passes through this set of points

* f(x) = -x² - 2x + 15 passes through (-2 , 15) , (-1 , 16) , (0 , 15)

- Now we have the first set of points and the third function

∴ The graph passes through this set of points

∴ f(x) = -x² + 2x - 15 passes through (0 , -15) , (1 , -14) , (2 , -15)

7 0
4 years ago
15 points!!<br> I need 10-18 if you know any please help me out!!
Mila [183]

Step-by-step explanation:

10.

angle QUR must be 180-41 = 139°

the reason : all angles on one side of the line QS around a single point (like U) must be 180°, as this represents a half-circle.

11.

the angle RUQ is larger.

the angle TUS is 90°.

therefore, SUN is 90° too. as well as TUQ and QUN.

the angle TUR is then TUS + 41 = 90+41 = 131°

and we know from 10. that QUR (or RUQ) is 139°.

therefore, RUQ is larger.

12.

when 2 lines cross, then the diagonally opposing angles are identical.

therefore,

84 = 4x

x = 21

13.

the same principle as in 10. applies.

all angles in one side of a line around a single point must be 180°.

so,

KMH + 84 = 180

KMH = 96°

14.

EBD = 90°

therefore, also ABE = 90°.

and we can imagine that BE extends straight to the other side of B having a point G there.

and then ABG = DBG = 90° as well.

and because these 90° angles and the principle of 12., we have

ABF = CBD = 90-62 = 28°

therefore,

CBE = CBD + DBE = 28 + 90 = 118°.

15.

ABF = 28°

as we calculated that in 14 already.

16.

due to the principles of 14 and 10 we have

CBA = 180 - CBD = 180 - 28 = 152°.

17.

this is not relevant to any of the pictures before.

angle A = angle B + 4

complementary angles are together 90°.

so,

A + B = 90

now we use the identity of the first equation in this main equation :

(B + 4) + B = 90

2B + 4 = 90

2B = 86

B = 43°

=>

A = B + 4 = 43 + 4 = 47°

18.

again, this is not related to any of the pictures before.

supplementary angles are together 180°.

D = 5E

D + E = 180

5E + E = 180

6E = 180

E = 30°

=>

D = 5E = 5×30 = 150°

5 0
3 years ago
Answer please I’m really struggling with this
katovenus [111]

To write the any polynomial in standard form you must first put it in terms separated only by +,- operators, then you must order terms x^n descendingly according to n. In your case -\frac{1}{5}x^2 will be the first term because it has highest power, followed by -8x^1 and +7x^0.

The standard form of this specific polynomial is:

-\dfrac{1}{5}x^2-2x+7.

Hope this helps.

6 0
3 years ago
Which of the following is equivalent to 18 minus the square root of -25
Stels [109]

Answer:

Undefined

Step-by-step explanation:

Since you said to find the square root of "-25" the answer is undefined because you cannot square root a negative number.

7 0
3 years ago
Read 2 more answers
Triangle U S T is shown. Angle U S T is 100 degrees. The length of U S is 9, the length of S T is 10, and the length of U T is s
Vladimir [108]

By solving through law of cosines the length s can be written as s^{2} =9^{2} +10^{2} -2*9*10cos(100).

Given the length of US is 9, the length of ST is 10 and the length of UT is s and the angle UST is 100 degrees.

According to law of cosines a length can be written as c^{2} =a^{2} +b^{2} -2abcos g

where c is the side opposite to the given angle and a and b are other sides , g is the angle given.

s^{2} =9^{2} +10^{2} -2*9*10cos(100)

where s is the length of the side opposite to the angle given, the length of other sides are 9 and 10 where the angle is 100.

Hence the fourth option is correct which is s^{2} =9^{2} +10^{2} -2*9*10cos(100).

Learn more about trigonometric functions here brainly.com/question/24349828

#SPJ10

6 0
2 years ago
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