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3 years ago

5

Mr. McDonald finds the lower the price of hamburgers in his restaurant, the more hamburgers he sells. This relationship can best

be identified as a _______ relationship.

1 answer:

Alla [95]3 years ago

6 0

Answer:

Negative linear relation

Step-by-step explanation:

When one variable increases (the price) while the other variable decreases (the number of hamburgers he sells) , a negative linear relationship exists.

The photo below may help you.

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The value of the surface area (in square centimeters) of the cone is equal to the value of the volume (in cubic centimeters) of

Dovator [93]

Answer:

The height of the cone is 10.9 cm

Step-by-step explanation:

step 1

Find the height of the cone

Applying the Pythagoras Theorem

$12^{2}=5^{2}+h^{2}$

$144=25+h^{2}$

$h^{2}=144-25$

$h^{2}=119$

$h=10.9\ cm$

therefore

The height of the cone is 10.9 cm

6 0

3 years ago

An angle measures 42° more than the measure of its complementary angle. What is the measure of each angle?

Vanyuwa [196]

Answer:

24° and 66°

Step-by-step explanation:

Angle 1 = x

Angle 2 = x + 42°

x + x + 42° = 90°

Subtract 42° from both sides and add

2x = 48°

Divide by 2

x = 24°

24° and 66°

Hope this was useful to you!

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!! THE RIGHT ANSWER WILL GET THE BRAINIEST!

Lina20 [59]

Answer:

$\sf D) \quad s=8 \frac{1}{4}t$

Step-by-step explanation:

t = time (in hours) → this is the independent variable
s = total area cleaned (in square feet) → this is the dependent variable (as the number of square feet cleaned depends on the number of hours worked)

Therefore, if the rate of cleaning is 8 1/4 square feet per hour, the relationship between s and t is:

$\sf s=8 \frac{1}{4}t$

8 0

2 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

2 years ago

Perchlorate is a chemical used in rocket fuel. People who live near a former rocket-testing site are concerned that perchlorate

ser-zykov [4K]

Answer:

$H_1 : \mu > 24.5$

Step-by-step explanation:

From the given information:

The sample size is 28

The population mean is 24.5 (ppb)

The sample mean is 225.3 (ppb)

Thus, the null and the alternative hypothesis can be computed as:

Null hypothesis:

$H_o : \mu \le 24.5$

Alternative hypothesis:

$H_1 : \mu > 24.5$

8 0

2 years ago