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Ivan
2 years ago
7

Prove: For all sets AB,and CIA-B) U (A n B) = A

Mathematics
1 answer:
joja [24]2 years ago
8 0

Answer:

Step-by-step explanation:

(A-B)U (A∩B)  [   We know that difference of A and B is A∩B')

A∩B')U(A∩B)    

A∩(B'UB)      (Using Distributive law)

A∩(U)            [ Union of a set and its complement is always a universal set]

A                        Hence proved

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Evaluate 4a + 7b + 3a − 2b for a = 5 and b = −3.
blsea [12.9K]

Answer:

<h2>20</h2>

Step-by-step explanation:

4a+7b+3a-2b\qquad\text{combine like terms}\\\\=(4a+3a)+(7b-2b)\\\\=7a+5b\qquad\text{put a = 5 and b = -3 to the expression}\\\\7(5)+5(-3)=35-15=20

5 0
3 years ago
Can someone answer this for me.
Marina CMI [18]

Answer:

A)  slope is 2/5 (positive slope)

B) slope is -2/6 (negative slope)

C) Yes, with different points, the slope remains the same.

3 0
2 years ago
Read 2 more answers
What is the value of x3 × y1 when x = 5 and y = 10​
katovenus [111]

Answer:

150

Step-by-step explanation:

To solve the problem, put 5 instead of x, so 5*3

and put 10 instead of y, so 10*1

when combined,

(5*3) * (10*1)

= 15 * 10

= 150

Hope this helps!!

Let me know if I'm wrong...

8 0
2 years ago
What is the gcf In this problem
scoray [572]
Find the GCF of 88 and 24 first 

88=2*2*2*11 
24=2*2*2*3 

The GCF for 88 and 24 is 8 
The GCF for r^18 and r^13 is r^13 (because they both contain r^13 in them) 

=8r^13(11, 3) 

Hope I helped :) 
8 0
2 years ago
Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy cla
My name is Ann [436]

Answer: Choice C

Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

======================================================

Explanation:

Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.

Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.

Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.

-----------------

In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.

Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.

8 0
3 years ago
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