The answer is D) 1/4
We draw the triangle and we notice triangle ABC is similar to DBE so all the sides will be in proportion.
Since AC is 4 times longer than DE, all the sides of triangle ABC will be 4 times longer.
Then if the perimeter of ABC was lets say 8, DBE would have a perimeter of 2.
D is the answer :)
<h3>
Answer: See the diagram below</h3>
The five number summary you wrote out is correct.
The tip of the left whisker is at 36, since this is the smallest value and we don't have outliers. The tip of the right whisker is at 64 which is the max (we don't have outliers here either).
The left and right edges of the box are Q1 and Q3 respectively. The median is the vertical line inside the box. The vertical line does not have to be at the midpoint as the diagram shows.
The IQR (interquartile range) is found by computing IQR = Q3-Q1 = 55-39 = 16
Note that the lower fence is L = Q1 - 1.5*IQR = 39 - 1.5*16 = 15. Anything below this value of L is an outlier.
The upper fence is U = Q3 + 1.5*IQR = 55 + 1.5*16 = 113.5; anything above this value of U is an outlier. All of the values in the given set are between L and U, meaning we don't have outliers. If we had outliers, then we would have island points outside the main box-and-whisker plot.
I used GeoGebra to create the box-and-whisker plot.
A=3.14r^2
1. 2^2= 4
2. 3.14 x 4 =12.56 as your answer
Answer:
3<u>i </u>- 5<u>j</u>.
Step-by-step explanation:
Consider the x-coordinates : 0 - (-3) = 3
Consider the y coordinates: 1 - 6 = -5
So the required vector is 3<u>i </u>- 5<u>j</u>.
Answer:
Venn is the circles and the tree is the green one (ignore the other thing on tree)