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irga5000 [103]
3 years ago
6

Need this answered ASAP

Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

Answer:

-24 it -5 all the time

Step-by-step explanation:

good luck

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You will write a 5-paragraph essay explaining how you would solve the following equation:
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Answer:

x=0

Step-by-step explanation:

\frac{7}{3}(2x+3)+\frac{3}{4}(\frac{x}{5}-\frac{15}{2})=\frac{11}{8} <-- Given

\frac{14}{3}x+7+\frac{3}{20}x-\frac{45}{8}=\frac{11}{8} <-- Distributive Property

\frac{280}{60}x+7+\frac{9}{60}x-\frac{45}{8}=\frac{11}{8} <-- Find LCD of x-terms

\frac{289}{60}x+7-\frac{45}{8}=\frac{11}{8} <-- Combine Like Terms

\frac{289}{60}x+7=\frac{56}{8} <-- Add 45/8 to both sides

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3 0
2 years ago
Consider the equation 5x^2-10x+c=0. What values of c result in the equation having a complex solutions? Represent your answer on
stiv31 [10]

Answer:

When we have a quadratic equation:

a*x^2 + b*x + c = 0

There is something called the determinant, and this is:

D = b^2 - 4*a*c

If D < 0, then the we will have complex solutions.

In our case, we have

5*x^2 - 10*x + c = 0

Then the determinant is:

D = (-10)^2 - 4*5*c = 100 - 4*5*c

And we want this to be smaller than zero, then let's find the value of c such that the determinant is exactly zero:

D = 0 = 100 - 4*5*c

    4*5*c = 100  

       20*c = 100

            c = 100/20 = 5

As c is multiplicating the negative term in the equation, if c increases, then we will have that D < 0.

This means that c must be larger than 5 if we want to have complex solutions,

c > 5.

I can not represent this in your number line, but this would be represented with a white dot in the five, that extends infinitely to the right, something like the image below:

8 0
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