<span>Find the inverse of the given function.
f(x) = -1/2√x + 3, x ≥ -3
I will have to assume that you meant f(x) = -(1/2)sqrt(x) + 3. If you actually meant f(x) = -(1/2)sqrt(x+3), then obviously the correct result would be different.
1. Replace "f(x)" by "y:" y </span>= -(1/2)sqrt(x) + 3
2. Interchange x and y: x = -(1/2)sqrt(y) + 3
3. Solve for y: x-3=-(1/2)sqrt(y), so that 2(3-x)= sqrt(y) and y=+sqrt(2[3-x])
4. Replace "y" with
-1
f (x) = sqrt(2[3-x])
Here, there are restrictions on x, since the domain of the sqrt function does not include - numbers. The domain here is (-infinity,3]
21+
15
2
+
3
2
+
15
13
LCD = 1515
21+
15
2
+
3×5
2×5
+
15
13
21+
15
2+10+13
21+1
15
10
22
15
10
15
10
3
2
22
3
2
done
the answer of this question is last one
<h3>
<u>Explanation</u></h3>

A constant inside the square root will make the graph shift either left to right, depending on the number. From the equation. The graph shifts to right two units.
A constant outside the square root will make the graph shift up or down, depending the value. From the equation, the graph shifts up 3 units.
<h3>
<u>Answer</u></h3>
- Second Image, the first one where x = 2 and y = 3.
480 bottles because 300 divided by 5 is 60 so then you multiply 60 by 8 and you get 480!
The exponent 4 needs to be applied to both 3 and x, so we would have:
3 * 3 * 3 * 3 * x^4.
9 * 9 * x^4.
81x^4