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sdas [7]
3 years ago
6

Find x in the equation x² - 7 = 4x + 5

Mathematics
2 answers:
VMariaS [17]3 years ago
6 0

Answer: 6 , -2


Step-by-step explanation:


Anarel [89]3 years ago
4 0
the awnser is 6,-2
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NISA [10]

Answer:

50,000,008,000

Step-by-step explanation:

3 0
3 years ago
A toy store marks down every toy by 15% in January. How much does a toy cost during January? Use p for the price in December.
Vinil7 [7]

Answer:

s=p−(p⋅d) .      0.75p

Step-by-step explanation:

6 0
3 years ago
What's the value of given expression :<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B8%20%5Ctimes%202%7D%20" id="TexForm
Drupady [299]

Answer:

\sqrt{8 \times 2}   \\ =  \sqrt{16}  \\  =  \sqrt{4 \times 4}  = 4 \\ thank \: you

8 0
2 years ago
Read 2 more answers
Assume that cost is 2 times more important than reputation and reputation is 3 times more important than compatibility with exis
dusya [7]
Let the weightage of Ease of Use be x
Ease of Use = x

<span>Compatibility is 5 times more than ease of use:
</span>Compatibility = 5x

<span>Reputation is 3 times more important than compatibility:
</span>Reputation = 3(5x)
Reputation = 15x

<span>Cost is 2 times more important than reputation:
</span>Cost = 2(15x)
Cost = 30x

So the weightage are:
Ease of Use : 1
Compatibility : 5
Reputation :15
Cost : 30
7 0
3 years ago
usa el teorema de la altura para proponer como se podria construir un segmento cuya longitud sea media proporcional entre dos se
Mrac [35]
Usando el teorema de altura 

El teorema de altura relaciona la altura (h) de un triángulo rectángulo (ver figura) y los catetos de dos triángulos que son semejantes al anterior ABC, al trazar la altura (h) sobre la hipotenusa. De manera que e<span>n todo </span>triángulo rectángulo, la altura (h<span>) relativa a la </span>hipotenusa<span> es la </span>media geométrica<span> de las dos proyecciones de los </span>catetos<span> sobre la </span>hipotenusa<span> (</span>n<span> y </span>m<span>). Es decir, se cumple que:

</span>\frac{n}{h}= \frac{h}{m}

Dado que el problema establece <span>construir un segmento cuya longitud sea media proporcional entre dos segmentos de 4 y 9 cm, entonces, digamos que n = 4cm y m = 9cm tenmos que:

</span>\frac{4}{h}= \frac{h}{9}

De donde:

h= \sqrt{(4)(9)}=\sqrt{36}=6cm

¿Cómo se podria construir si los segmentos son de a cm y b cm?

Si los segmentos son de a y b cm entonces a y b son parámetros que pueden tomar cualquier valor positivo siempre que se cumpla que:

h= \sqrt{ab}

6 0
3 years ago
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