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Ipatiy [6.2K]
3 years ago
13

Which of the following best explains how a scanning electron microscope is used to produce an image of a specimen? An electron b

eam strikes the specimen, is absorbed by the specimen, and used to produce an electrically charged image on a screen. An electron beam passes over the specimen’s surface and displaces electrons, which are then focused on a screen to form an image. An electron beam traces an outline of the specimen onto a screen, and reflected electrons are collected to form the rest of the image. An electron beam travels through the specimen, and as it does so it burns an image of the specimen on a screen.
Biology
2 answers:
victus00 [196]3 years ago
8 0

The correct answer is B) An electron beam passes over the specimen's surface and displaces electrons, which are then focused on a screen to form an image.

torisob [31]3 years ago
8 0

Answer: An electron beam passes over the specimen's surface and displaces electrons, which then focused on a screen to form an image.

A scanning electron microscope is a microscope which studies the surface characteristics of the specimen. It focuses an electron beam over a surface of the specimen to create an image. Electron beam supplied by scanning electron microscope interact with the surface of the specimen. The reflected electrons also known as back scattered electrons are collected to create image on the screen.

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Pyruvate dehydrogenase is regulated by feedback inhibition and covalent modification. Which molecules inhibit the pyruvate dehyd
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ADP, NAD+, CoA-SH, and pyruvate are the molecules that inhibit the pyruvate dehydrogenase complex.

<h3>What is pyruvate dehydrogenase complex?</h3>

PDC3 triggers the oxidative decarboxylation of pyruvate, resulting in the creation of acetyl-CoA, CO2, and NADH.

The PDC plays a crucial role in the oxidation of glucose by connecting the glycolytic pathway to the tricarboxylic acid cycle's oxidative pathway.

ADP, NAD+, CoA-SH, and pyruvate all inhibit it. PDK prevents glycolysis from being coupled to GO by inhibiting its target enzyme PDH.

Thus, the answer is ADP, NAD+, CoA-SH, and pyruvate .

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What is the vaccine for tuberculosis???​
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Which of the following organelles would be affected first if there were no lipids present to allow nutrients to enter the cell a
Volgvan
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For each region of the lac operon on the F' plasmid, I+ P+ Oc Z− Y+ , determine whether the region is wild type (that is, it pro
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Answer:

A,B and E

Explanation:

  • I+: I refers to the lac repressor, the + indicates that the repressor is functional
  • P+:  P refers to the promoter region and the + indicates that the promoter is functional
  • Oc:  O refers to the operator region, but the Oc indicates that the operator is constitutive ie. that it is always on/ can't be turned off.
  • Z-: Z refers to the LacZ gene which produces β-galactosidase. Z- indicates that this gene is non-functional
  • Y+:  Y refers to the LacY gene which produces the permease protein. Y+ indicates that this gene is functional

So based on the breakdown above:

  • A is true because P+.
  • B is true because I+.
  • C is not true because the lac operon is an inducible system. The operator needs to be able to be repressed. In this case the operator is constitutive (always on)  which is not the correct form.
  • D is not true because Z-, no β-galactosidase is produced.
  • E is true because Y+.

Only A, B and E apply.

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3 years ago
What molecule that is created during photosynthesis provides energy for cellular processes?
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Answer: D) glucose

Explanation: 100% sure this is the correct answer.( Also took the quiz and got it right.)

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