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shutvik [7]
3 years ago
9

Which of the following equations has a graph that passes through (3, 3) and has a slope of −2?

Mathematics
2 answers:
Tatiana [17]3 years ago
7 0

Answer:

y - y1 = m(x - x1)

y - -3 = 3(x - 1)

y + 3 = 3x - 3

     y = 3x - 3 - 3

     y = 3x - 6

     y = 3x - 6

Step-by-step explanation:

Thie equation is in slope-intercept form (y = mx + b)

The y-intercept is -6 .... ((0, -6) is one point on the line.

It is given that (1, -3) is also on the line. So to graph, plot those

2 points and connect them with a line.

Hatshy [7]3 years ago
7 0

Answer:

y = -2x+9

Step-by-step explanation:

We have a point and a slope

y = mx+b where m is the slope and b is the y intercept

y = -2x +b

Substitute the point in

3 = -2(3)+b

3 = -6+b

Add 6

3+6 = -6+6+b

9 = b

y = -2x+9

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Natasha2012 [34]

Answer: -6 -2

Step-by-step explanation:

6 0
2 years ago
David made a triangle with sides 6 cm, 9cm , 12 cm. George wanted to make a triangle bigger in size but similar to that drawn by
SashulF [63]

Step-by-step explanation:

Given :

\triangle ABC \sim \triangle XYZ .△ABC∼△XYZ.

AB = 6\:cm, \:BC = 9 \:cm, CA = 12 \:cmAB=6cm,BC=9cm,CA=12cm

Let \: XY = 10\:cm, \:YZ = x \:cm, \: XZ = y /:cmLetXY=10cm,YZ=xcm,XZ=y/:cm

\frac{AB}{XY} = \frac{BC}{x} = \frac{CA}{y}XYAB=xBC=yCA

\blue {( The \: lengths \:of \: corresponding }(Thelengthsofcorresponding

\blue {sides \:are \: proportional .)}sidesareproportional.)

\implies \frac{6}{10} = \frac{9}{x} = \frac{12}{y}⟹106=x9=y12

i) \implies \frac{6}{10} = \frac{9}{x}i)⟹106=x9

\implies x = \frac{9 \times 10}{6}⟹x=69×10

\implies x = 15\:cm⟹x=15cm

ii) \implies \frac{6}{10} = \frac{12}{y}ii)⟹106=y12

\implies y = \frac{12 \times 10}{6}⟹y=612×10

\implies y = 20\:cm⟹y=20cm

Therefore.,

\red { Value \:of \:x } \green { = 15\:cm }Valueofx=15cm

\red { Value \:of \:y } \green { = 20\:cm }Valueofy=20cm

•••♪

8 0
2 years ago
Given that the mass of an average linebacker at Ursinus College is 250 lbs and the radius of a pea is 0.50 cm, calculate the num
Brilliant_brown [7]

Answer:

1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle

Step-by-step explanation:

Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is

V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³

the mass in that volume would be  m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)

The density of an alpha particle is  ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be

ρ= m/V

since both should be equal ρ=ρa , then

ρa= m/V =N*L/V → N =ρa*V/L

replacing values

N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg  = 1.544*10⁹ Linebackers

N=1.544*10⁹ Linebackers

7 0
3 years ago
Lines of ________________ run north and south but measure east and west. *
wolverine [178]

Answer:

prime meridian

Step-by-step explanation:

look it up

4 0
3 years ago
Read 2 more answers
HURRY PLS ANSWER NOW!!
ivolga24 [154]

Answer:

91 in2

Step-by-step explanation:

11+15 over 2 , times by 7 equals 91 ??

8 0
2 years ago
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