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arlik [135]
3 years ago
10

If AD = y + 6 and DC = 2y, what is the length of DC? 12 -12 -15 15

Mathematics
2 answers:
babymother [125]3 years ago
5 0
Y+6=2y
-y=-6
y=6
The length of DC is 12
Ira Lisetskai [31]3 years ago
5 0

Answer:

DC=12\ units

Step-by-step explanation:

Step 1

<u>Find the value of y</u>

In this problem we know that

AD=DC -----> equation A

ED=DB

see the attached figure to better understand the problem

so

we have

AD=y+6

DC=2y

substitute the values in the equation A

y+6=2y

solve for y

2y-y=6

y=6\ units

Step 2

Find the value of DC

we have that

DC=2y

substitute the value of y

DC=2(6)=12\ units


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Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

7 0
2 years ago
2/9 h = 8<br><br> h=<br><br> Pls tell me what h = !
Wewaii [24]

Answer:

h=36

.......................

3 0
3 years ago
Cami and Enrique's ages add up to 46. Cami is two years older than three times Enrique's age. How old are Cami and Enrique?
stira [4]

answer:

Cami is 35 and Enrique is 11

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3 0
3 years ago
I need help please and thank you
Pachacha [2.7K]

My answers are in the picture above.

8 0
3 years ago
Read 2 more answers
Can someone explain why A is the right answer to this question? I'm unsure of how to work out this problem.
joja [24]

So firstly, we have to find the radius of the circular garden before finding the circumference (the amount of fencing needed to surround the garden). To find the radius, use the area formula (A=\pi r^2), plug in the area of the garden (36 ft^2) and solve for r as such:

36=\pi r^2\\ \frac{36}{\pi}=r^2\\ \frac{\sqrt{36}}{\sqrt{\pi}}=r\\ \frac{6}{\sqrt{\pi}}=r

So that we know the radius, plug that into the circumference equation (C=2\pi r) to solve:

C=2\pi*\frac{6}{\sqrt{\pi}}\\ C=\frac{12\pi}{\sqrt{\pi}}\\ C=12\sqrt{\pi}

Your answer is A. 12√π.

4 0
3 years ago
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