Answer:
kjvdfvnfjv
Step-by-step explanation:rjfnu4fburbf
Answer:
210 cm2
Step-by-step explanation:
Length of the diameter = sqrt ( (-12- (-8)^2) +(2-0)^2) )
= sqrt (16 + 4) = sqrt20
so radius = sqrt 20 / 2 = sqrt5
so r^2 = 5
Center of the circle = coordinates of the midpoint of the diameter =
-8-12/2 , 2-0 / 2 = (-10, 1)
(x - a)^2 + (y - b)^2 = r^2 is general form of a circle so here the circle is:_
(x + 10)^2 + (y - 1)^2 = 5 Answer
Its B
Answer:
w =< 70
(width is less or equal to 70 inches)
Step-by-step explanation:
Let l = length, w = width, h = height
Restrictions given in this question:
'sum of perimeter of the base and the height cannot exceed 130 inches'
perimeter of the base is 2 width and 2 length of the box
perimeter = 2w + 2l
Therefore, inequality involves here is
2w + 2l + h =< 130
(Note that =< here means less or equal)
Then a new condition given with
height, h = 60 in
and length is 2.5 times the width
l = 2.5w
Substitute this new condition into the equation will give us the following:
2w + 2(2.5w) + 60 =< 130
2w + 5w + 60 =< 130
7w + 60 =< 130
7w =< 130-60
7w =< 70
w =< 10
