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2 years ago

Please help quick! This is due tomorrow for class and I really need help! Thank you.

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

7 0

0.8inch = 2.032
1.4inch = 3.556
2.1inch = 5.334

Sorry if its wrong had to do it fast!!!

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Please help asap for a test

son4ous [18]

Answer: y=4x−1

good luck

8 0

2 years ago

Read 2 more answers

Tickets for a dance recital cost $15 for adults and $7 for children. The dance company sold 253 tickets, and the total receipts

elixir [45]

Answer:

Adult tickets =125

Child tickets = 128

Step-by-step explanation:

Let the number of adult and children tickets sold be x and y respectively

So that

x+y= 253--------1

Since total sales/receipt is $2,771

And given that tickets for a dance recital cost $15 for adults and $7 for children hence

15x+7y= 2771-------2

Solving equation 1 and 2 simultaneously we have

x+y= 253---------------1

15x+7y= 2771----------2

Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3

15x+15y=3795---------3

-{15x+7y= 2771----------2

0+8y=1024

8y= 1024

y= 1024/8

y= 128 tickets

So solve for x let us put y= 128 in equation 1

x+ 128=253

x=253-128

x= 125 tickets

8 0

3 years ago

!!!please for the love of God help me!!!

Grace [21]

<h3>Given :-</h3>

$\\$

x=y-1
x+2y=8

$\\$

$\\$

Value of x
Value of y

$\\$

<h3>Solution:-</h3>

Let say it is first equation:-

x=y-1. . . . (1)

and this is second equation:-

x+2y=8 . . . . (2)

$\\ \\$

Simplifying 1 equation:-

x = y - 1
x +1 = y
y = x + 1

Put this value of y in second equation.

$\\$

$\dashrightarrow \sf \: x+2y=8$

$\\$

$\dashrightarrow \sf \: x+2(x + 1)=8$

$\\$

$\dashrightarrow \sf \: x+2x +2=8$

$\\ \\$

$\dashrightarrow \sf \: 3x +2=8$

$\\ \\$

$\dashrightarrow \sf \: 3x=8 - 2$

$\\ \\$

$\dashrightarrow \sf \: 3x=6$

$\\ \\$

$\dashrightarrow \sf \: x=6 \div 3$

$\\ \\$

$\dashrightarrow \sf \: x= \bf2$

$\\$

to find value of y :-

y = x + 1

y = 2 + 1

y = 3

$\\$

verification:-

$\\$

1 equation:-

x = y - 1

put value of x and y

2 = 3 - 1

2 = 2

LHS = RHS

Hence verified!

$\\$

2 equation:-

$\\$

x+2y=8

put value of x and y

2 + 2 × 3 = 8
2 + 6 = 8
8 = 8

LHS = RHS

Hence verified!

$\\$

Both equation verified!

.°. value of x and y is 2 and 3 respectively

7 0

2 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

3 years ago

Write the standard form equation for the line: y+1=-45(x+5).

sergij07 [2.7K]

The answer is 45x+y=-226. Hope this helps :)

5 0

2 years ago

Please help quick! This is due tomorrow for class and I really need help! Thank you.￼￼

Please help quick! This is due tomorrow for class and I really need help! Thank you.