All categories

3 years ago

Please help quick! This is due tomorrow for class and I really need help! Thank you.

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

7 0

0.8inch = 2.032
1.4inch = 3.556
2.1inch = 5.334

Sorry if its wrong had to do it fast!!!

You might be interested in

the corresponding side of two rectangular swimming pools are 66 feet and 44 feet if the perimeter of the larger pool is 198 feet

morpeh [17]

Add them together p= a+b=c

5 0

3 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago

The children from a football club are put into rows in the sports hall. When put into rows of 9 children, there are 2 children l

g100num [7]

We are told that the children from a football club are put into rows in the sports hall. When put into rows of 9 children there are 2 children left over. When put into rows of 12 children there are 2 children left over.

We will find least number of children in football club by finding LCM of 9 and 12.

Multiples of 9 are: 9, 18, 27, 36, 45, 54, 63,...

Multiples of 12 are: 12, 24, 36, 48, 60, 72, 84,...

We can see that least common multiple of 9 and 12 is 36.

We are told that 2 children left over from putting them into 9 and 12 children per row. To find least number we will add 2 to 36.

$9\cdot4+2=36+2=38$

$12\cdot3+2=36+2=38$

$\text{Least number of children in football club}=36+2=38$

Therefore, the least number of children in the football club is 38.

5 0

3 years ago

The answer to an addition problem<br>

Vikki [24]

The answer is sum :)

6 0

3 years ago

At a banquet hall, each table requires 18 plates. The kitchen has 387 plates available. How many full tables can be set?

N76 [4]

21 full tables because if you divide the amount of plates you have by the amount of plates needed for each table you’ll get 21.5 but they asked for full tables so that would be 21

7 0

3 years ago

Please help quick! This is due tomorrow for class and I really need help! Thank you.￼￼

Please help quick! This is due tomorrow for class and I really need help! Thank you.