Answer:
At least 13 chocolates must be removed
Step-by-step explanation:
If there are three flavors, the probability of drawing 1 would be: 1
1/3 = 0.333
Which means, that every 3 attempts, theoretically you should do 1 of each, but how they ask for 5 chocolates of each would be:
3 * 5 = 15
At least 15 chocolates must be extracted to theoretically guarantee 5 chocolates each, but how we are interested in knowing is that a single flavor has 5 chocolates, so we discard the last two chocolates that represent the other two flavors
Therefore, for there to be safely 5 chocolates of the same flavor, at least 13 chocolates must be removed.
Answer:
the probability that Jack draws the blue ball is 0.38539
Step-by-step explanation:
Given the data in the question;
box contains
blue balls = 5
red balls = 8
Jim and Jack start drawing balls from the box, respectively, one at a time, at random, and without replacement
Now,
on the first attempted;
⇒ ( 8/13) × ( 5/12) = 10/39
on the second attempt;
⇒ ( 8/13 ) ( 7/12) ( 6/11 ) ( 5/10 ) = 14/143
on the third attempt;
⇒ ( 8/13 ) ( 7/12) ( 6/11 ) ( 5/10 ) ( 4/9 ) ( 5/8 ) = 35/1287
on the fourth attempt;
⇒ ( 8/13 ) ( 7/12) ( 6/11 ) ( 5/10 ) ( 4/9 ) ( 3/8 ) ( 2/7 ) ( 5/6 ) = 5/1287
so we add everything;
⇒ 10/39 + 14/143 + 35/1287 + 5/1287
= 0.38539
Therefore, the probability that Jack draws the blue ball is 0.38539
Sorry I need to ask more questions
Answer:
sorry but I don't know the answer