Answer:
x = 1.2...
Step-by-step explanation:
Start with the given equation and isolate the variable.
6.2x + 1.2 = 8.9
Subtract 1.2 from each side:
6.2x = 7.7
Divide each side by 6.2:
x = 1.2...
m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°
Solution:
Line
intersect at a point W.
Given
.
<em>Vertical angle theorem:</em>
<em>If two lines intersect at a point then vertically opposite angles are congruent.</em>
<u>To find the measure of all the angles:</u>
∠AWB and ∠DWC are vertically opposite angles.
Therefore, ∠AWB = ∠DWC
⇒ ∠AWB = 138°
Sum of all the angles in a straight line = 180°
⇒ ∠AWD + ∠DWC = 180°
⇒ ∠AWD + 138° = 180°
⇒ ∠AWD = 180° – 138°
⇒ ∠AWD = 42°
Since ∠AWD and ∠BWC are vertically opposite angles.
Therefore, ∠AWD = ∠BWC
⇒ ∠BWC = 42°
Hence the measure of the angles are
m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°.
Answer:
Option A.) 20 pounds of walnuts and 25 pounds of almonds is correct.
Step-by-step explanation:
i) let x be the the number of pounds of almonds
ii) let y be the number of pounds of walnuts
iii) therefore x + y = 45 pounds of the mixture
iv) 1.2x + 0.75y = 1.00
45 = 45
v) Multipling equation in iv) by 4 we get
4.8x + 3y = 180
vi) multiplying equation in iii) by 3 we get
3x + 3y = 135
vii) subtracting equation vi) from equation v) we get 1.8x = 45
ix) therefore we get x = 45/1.8 = 25 pounds of almonds
x) therefore 25 + y = 45 .... substituting value of x from ix) in iii) we get
therefore y = 20 pounds of walnuts
Therefore option A.) 20 pounds of walnuts and 25 pounds of almonds is correct.
Answer:

Step-by-step explanation:
If we approximate the binomial distribution with a normal distribution, we have to apply a correction factor for the fact that we are now dealing with a continuous variable instead of a discrete one, as it was with the binomial distribution.
The probability of no more than 35 defective CDs: P(X<35)
In this case, as X=35 is not included in the interval, we start the interval from X=35-0.5=34.5.

being Pb the probability under the binomial distribution and Pn the probability under the normal distribution.
The area for the normal distribution is the one below X=34 (or P(X<34)).
Answer:
67
Step-by-step explanation:
GOOD LUCK!!