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Amiraneli [1.4K]

3 years ago

8

I need help with this question?????

1 answer:

inn [45]3 years ago

3 0

(5 cases)/(2 3/8 hour)
(5 cases)/(19/8 hours)
(5*8/19) cases/hour....invert the fraction and multiply 1/(19/8 hour)=(8/19)/hour
40/19 cases/hour
2 2/19 cases/hour

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I WILL GIVE YOU BRAINLIEST AND 20 POINTS, PLS HELP. K12 STUDENT.

EastWind [94]

36, |-12|=12 and |-3|= 3. Using inverse operations, we multiply instead of dividing and get 36.

5 0

4 years ago

Kiaraly answered 27 out of 30 questions correctly on her math test. Later she answered 22 of 25 questions correctly on her scien

STatiana [176]

It’s same because 30-27=3
25-22=3

5 0

4 years ago

Create an exponential to describe $100 at 2% interest, compounded annually, for x years. y=100(.98)^x y=100(.8)^x y=100(1.2)^x y

zysi [14]

The exponential to describe $100 at 2% interest, compounded annually, for x years is $y=100(1.02)^{x}$

<h3><u>Solution:</u></h3>

Given that $ 100 at 2 % interest , compounded annually for "x" years

<em><u>The formula for compound interest, including principal sum, is:</u></em>

$A=P\left(1+\frac{r}{n}\right)^{n t}$

A = the future value of the investment/loan, including interest

P = the principal investment amount (the initial deposit or loan amount)

r = the annual interest rate (decimal)

n = the number of times that interest is compounded per unit t

t = the time the money is invested or borrowed for

Here in this sum,

P = $ 100

$r = 2 \% = \frac{2}{100} = 0.02$

number of years = x

Here given that compounded annually , so n = 1

Let "y" be the amount after "x" years

Substituting the values in formula we get,

$\begin{aligned}&y=100\left(1+\frac{0.02}{1}\right)^{1 \times x}\\\\&y=100(1+0.02)^{x}\\\\&y=100(1.02)^{x}\end{aligned}$

Thus the exponential to describe is $y=100(1.02)^{x}$

5 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

you draw two marbles without replacement from a bag containing four red marbles, two Yellow Marbles and five blue marbles, find

AleksAgata [21]

A bag contains four red marbles, two Yellow Marbles and five blue marbles.

Two marbles are drawn at random without replacement.

Total number of marbles are,

$4\text{ + 2 + 5 = 11}$

There are 11 ways to select first marble and 10 ways to select second marble.

The total number of possible outcomes are calculated as,

$Total\text{ number of outcomes = 11 }\times\text{ 10 = 110 }$

Thus the total number of possible outcomes are 110.

7 0

1 year ago