Tbh idk I just need more points so I guess it's like alot or maybe a little but ask someone who knows
Answer:
3 and 9
if f(x)=x^2+13 and g(x)=12x-14
Step-by-step explanation:
So when we are looking for the intersection of two functions, we are trying to figure out when they are the same. When you think same, you should think equal (=).
So we want to find when f(x)=g(x) for x.
f(x)=g(x)

Let's get everything to one side.
Subtracting 12x and adding 14 to both sides.

I'm going to reorder the left hand side and also simplify the 13+14 part:

Now since the coefficent of x^2 is just 1 our job is to find two numbers that multiply to be 27 and add up to be -12.
Those numbers are -3 and -9 since -3(-9)=27 and -3+(-9)=-12.
So the factored form of our equation is

Since the product is 0, then at least one of the factors must be 0.
So we want to solve both x-3=0 and x-9=0.
x-3=0 can be solved by adding 3 on both sides. This gives us x=3.
x-9=9 can be solved by adding 9 on both sides. This gives us x=9.
The intersection of f and g happens at x=3 or x=9.
Answer:
angle B is 38 degree
Step-by-step explanation:
In triangle ADC,
finding angle C
angle A + angle C = 110 degree (sum of two interior opposite angles are equal to the exterior angle formed)
46 + angle C = 110
angle C = 110 - 46
angle C = 64 degree
In triangle ABC
finding angle B
angle A + angle B + angle C = 180 degree (sum of interior angles of a triangle)
78 + angle B + 64 = 180
142 + angle B = 180
angle B = 180 - 142
angle B = 38 degree

We use long division to divide
There is no x term in x^2 -1 so we put 0x
x + 1
----------------------------
x^2+0x-1 x^3+ x^2 + x+ 2
x^3+0x^2-x
-----------------------------(subtract the bottom from top)
x^2 +2x + 2
x^2 +0x - 1
--------------------------------(subtract the bottom from top)
2x + 3
-----------------------------------------
Quotient : x+1
Remainder : 2x+3