Answer:
N(2,3)
Step-by-step explanation:
According to the Question,
- Given that, In the triangle ABC. M is the midpoint of AB and N is the midpoint of CM And A(-1, 3), B(7-3) and C(1,6).
- Thus, For coordinates of N. first We have to find the Coordinate of M(x,y). As Given M is the Midpoint of A(-1, 3) and B(7-3).
Thus, M(x,y) = (-1+7)/2 , (3-3)/2 ⇒ M(3,0)
- Now, As Given, N(a,b) is the Midpoint Of C(1,6) and M(3,0).
Thus. N(a,b) = (1+3)/2 , (6+0)/2 ⇒ N(2,3)
If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
That is true because you are still dividing x by three either way
Answer:
Step-by-step explanation:
x![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx)
XE[_4.2,2.2]
Answer:
H₀: µ ≤ $8,500; H₁: µ > $8,500
z= +1.645
Step-by-step explanation:
From the given problem As average cost of tuition and room and board at a small private liberal is less than the financial administrator As hypothesis is true.
As standard deviation is $ 1,200
α = 0.05
H₀: µ ≤ $8,500
if the null hypothesis is true then value for critical z is +1.645.
