When testing for current in a cable with twelve color-coded wires, the author used a meter to test four wires at a time. How ma

Question

Ksivusya [100]

4 years ago

9

When testing for current in a cable with twelve color-coded wires, the author used a meter to test four wires at a time. How ma

ny different tests are required for every possible pairing of four wires?

Social Studies

1 answer:

MrRissso [65] · Answer 1 · 2022-01-05T10:30:32+03:00

MrRissso [65]4 years ago

4 0

Answer:

The no of tests required shall be 495.

Explanation:

The possible pairing shall be the number of different ways in which 4 wires can be selected among a group of 12 different wires which is given by combinatorics as

$\binom{n}{r}=\frac{n!}{r!(n-r)!}$

Applying values we get

No of required ways are = $\binom{12}{4}=\frac{12!}{4!(12-4)!}=495$

When testing for current in a cable with twelve ​color-coded wires, the author used a meter to test four wires at a time. How ma

When testing for current in a cable with twelve color-coded wires, the author used a meter to test four wires at a time. How ma