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seraphim [82]
2 years ago
5

there are some cows and some chickens, if there are a total of 40 heads and 112 legs, how many cows are there

Mathematics
2 answers:
Dominik [7]2 years ago
5 0

ummm I think I know but I don't at the same time take away 40 from 112 and theres you answer♥.



Serga [27]2 years ago
5 0
4x + 2(40-x) = 112
4x + 80 - 2x = 112
2x = 32
x = 16

so 16 cows and 24 chickens
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If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

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Now look at ΔADC.  Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>

Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.

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Answer:

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a\times10^k\ \text{where}\ 1\leq a

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\dfrac{4.5\times10^7}{1.5\times10^{-8}}=\dfrac{4.5}{1.5}\times\dfrac{10^7}{10^{-8}}

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