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seraphim [82]
3 years ago
5

there are some cows and some chickens, if there are a total of 40 heads and 112 legs, how many cows are there

Mathematics
2 answers:
Dominik [7]3 years ago
5 0

ummm I think I know but I don't at the same time take away 40 from 112 and theres you answer♥.



Serga [27]3 years ago
5 0
4x + 2(40-x) = 112
4x + 80 - 2x = 112
2x = 32
x = 16

so 16 cows and 24 chickens
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I hope this helps you


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3 years ago
Evaluate x(y+3)/(3+y)z for x=12, y=1, and z=6.<br><br> A) 2<br><br> B) 5<br><br> C) 8<br><br> D) 6
fgiga [73]

Answer:

2

Step-by-step explanation:

We take the equation

x(y+3)/(3+y)z

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12(1+3)/(3+1)6

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When solved, it equals 2.

5 0
3 years ago
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Solve the following pairs of simultaneous equations.
Sergeeva-Olga [200]

Answer and step-by-step explanation:

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2x + 3y = 21

Multiply the second equation by 2, you will get:

4x + 6y = 42 (1)

Use (1) plus with (2), you will get:

4x + (-4x) + 6y + 5y = -9 + 42

11y = 33

y = 33/11

y = 3

4x + 18 = 42

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x = 6

b) 2x + 5y = -6

3x + 2y = 2

Multiply first equation by 3, you will get:

6x + 15y = -18 (1)

Multiply the second equation by 2 and you will get:

6x + 4y = 4 (2)

Subtract (1) by (2), we got:

6x -6x + 15y - 4y = -18 - 4

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Multiply the first euation by 2, we got:

4x - 4y = -4 (3)

Use (3) minus for (2), we get:

4x - 5x -4y + 4y = -4 - 17

-x = -21

x = 21

4x - 4y = -4

84 - 4y = -4

-4y = -4 + 84

-4y = 80

y = 80 / -4

y = -20

d) 2x - 3y = 6

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Multiply the first equation by 2, we got:

4x - 6y = 12 (2)

Use (1) minus for (2), we got:

4x -4x - 5y - 6y = 9 -12

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y = -3/-11

y = 3/11

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Use the first equation subtract the second equation, we got:

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x/ 4 = -2

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x = -8

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y/3 = 6

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f) x/3 + y/2 = 3/2 (1)

x/2 + y/5 = -1/2 (2)

I don't know how to solve this, sr

Hope this helped :3

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A function is shown in the table.
Anna71 [15]
<span>Given:
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The true statement for the given function is:
</span><span>The function is decreasing from x = −3 to x = −1.
</span><span>
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</span>
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Answer:

A

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