Rewrite the equation by completing the square x^2+10x+16=0

A steel safe with mass 2200 kg falls onto concrete. Just

Virty [35]

The kinetic energy of the safe increases the force exerted by the concrete

to several times the weight of the safe.

The magnitude of the force exerted on the safe by the concrete on the is approximately $\underline{29.\overline 3 \, \mathrm{MN}}$

The concrete exerts a force that is approximately 1,359.16 times the weight of the safe.

Reasons:

First part

The mass of the steel safe, m = 2,200 kg

Velocity of the safe just before it hits the concrete, v = 40 m/s

The amount by which the safe was compressed, d = 0.06 m

The kinetic energy, K.E., of the safe just before it hits the round is therefore;

$\displaystyle K.E. = \mathbf{\frac{1}{2} \cdot m \cdot v^2}$

$\displaystyle K.E._{safe} = \frac{1}{2} \times 2,200 \times 40^2 = 1,760,000 \ Joules$

Work done by concrete, W = Force, F × Distance, d

$\displaystyle Force, \, F = \mathbf{\frac{Work, \, W}{Distance, \, d}}$

By the law of conservation of energy, we have;

The work done by the concrete, W = The kinetic energy, K.E. given by the safe

W = K.E. = 1,760,000 J

The effect of the work = The change in the height of the safe

Therefore;

The distance, d, over which the force of the concrete is exerted = The change in the height of the safe = 0.06 m

d = 0.06 m

Therefore;

$\displaystyle The \ force \ of \ the \ concrete, \, F = \frac{1,760,000\, J}{0.06 \, m} = 29,333,333. \overline 3 \, N = 29.\overline 3 \ MN$

The force of the concrete on the safe = $\underline{29.\overline 3 \ MN}$

Second part:

The gravitational force of the Earth on the safe, W = The weight of the safe

W = Mass, m × Acceleration due to gravity, g

W = 2,200 kg × 9.81 m/s² ≈ 21,582 N

The ratio of the force exerted by the concrete to the weight of the safe is found as follows;

$\displaystyle Ratio \ of \ forces = \frac{29.\overline 3 \times 10^6 \, N}{21,582 \, N} = \frac{4,000,000}{2,943} \approx \mathbf{1359.16}$

The force exerted by the concrete is approximately 1,359.16 times the weight of the safe.

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5 0

3 years ago

A solid concrete wall 4.0 m by 2.4 m and 30 cm thick, with a thermal conductivity of 1.3 w/(m·k), separates a basement at 18°c f

Nastasia [14]

THE AREA OF THE ROOM IS :A=4*2.4=9.6 m^2
THICKNESS t=0.30 m
DIFFERENCE IN TEMPERATURE dT=18-6=12
q=kAdT/dx=kA*dT/t
q=1.3(9.6)(12)/0.30=4992 W=499.2 J/s
In 1 hour or 3600 sec
P=q*T=(499.2 J/s)(3600 s)=1797120 J=1.8 MJ
1.8MJ OF HEAT FLOWS HTROUGH THE WALL IN ONE HOUR

5 0

3 years ago

15 = 3w solve for w, what does w equal

Vlada [557]

Answer:

w = 5

Step-by-step explanation:

15 = 3w

Switch sides.

3w = 15

Divide both sides by 3.

w = 5

6 0

3 years ago

Read 2 more answers

how many calories burned in 1 hour of jumping jacks? If 10 minutes of jumping jacks is 100 calories burned?

astra-53 [7]

Answer:

600 calories

Step-by-step explanation:

60/10 = 6

6 x 100 = 600

3 0

3 years ago

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Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 685 randomly s

jek_recluse [69]

Answer:

417 is the number of adults that would erase their personal information online if they could, they are the 61%. The complete number is 417,85, but we have to adjust the answer for people.

Step-by-step explanation:

To find the answer we need to do a Rule of Three. The Rule of Three is a Mathematical Rule that will help us to solve problems based on proportions.

1. I know that a 685 adults were surveyed, so this is the 100%. 61% say they would erase all of their personal information online if they could, and we don't know the numbre of people in here.

2. So 685 adults _____ 100%

X adults _____ 61%

Here we have to put the same elements in the same columns. Students with studients and percentage with percentage.

3. Now I have to cross these details. I have to multiple 61*685. So:

61*685= 41785

4. Then divide that result by 100.

41785/100= 417,85

5. So 417 is the total number of adults that would .

6 0

4 years ago