NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by
The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:
Using the quadratic formula, the solution for our problem is
The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have
The root is
Then, the maximum height is
1029.99 meters above sea level.
The answer is: J - 3.08 pounds
Answer:
20%
Step-by-step explanation:
Generic exponential growth model: y = Ao[1+r]^t
In this case: r = 3.5% = 0.035
y = 2Ao .....[the double of the initial value]
Then: 2Ao =Ao (1 + 0.035)^t
(1.035)^t =2
Take logarithm to both sides
t ln(1.035) = ln(2)
t = ln(2) / ln(1.035) = 0.693 / 0.0344 = 20.15
Answer: 20.15 hours.
Answer: 25 ounces
Step-by-step explanation:
The equation would be 0.2∙25+0∙x=0.1(25+x) because 20% of boric acid would be = to 0.2. water doesn't have any acid in it so it would be 0. since annabel wants a 10% solution that would mean that the total about would be 0.1 of boric acid. The ounces she needs for the 0.2 boric acid solution is 25 while the other is unknown so that would be x. when you put them together it would be 25+x. then you just multiply the ounces and the acid together and you get 0.2∙25+0∙x=0.1(25+x). when you solve it it would be x=25.
