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svetoff [14.1K]
3 years ago
5

Write a real world problem that can be solved using the equation 38 divided by 5 = 7 r 3

Mathematics
1 answer:
notka56 [123]3 years ago
7 0
You are having a birthday party and invited 38 people.  Each table you rented only sits 5 people. 
 
How many tables would you need to rent for everyone to have a place to sit? <span>You would have to rent the 8th table for the remaining 3 people to sit at. </span>

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What does x equal to
Sergio [31]

Answer:

1/6 x + 27 combine like terms to get the answer :)

Step-by-step explanation:

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2 years ago
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In ΔEFG, the measure of ∠G=90°, the measure of ∠E=40°, and EF = 75 feet. Find the length of GE to the nearest tenth of a foot.
Vikki [24]

Answer:

57.453 ft

Step-by-step explanation:

Glad to help ! :)

3 0
2 years ago
I don’t understand this. Please help
svlad2 [7]

Answer:

x = 150

Step-by-step explanation:

(n-2)180       (n = the amount of sides)

(12 - 2)180

(10)180

1800

1800/12 = 150

7 0
2 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
4x-5y+2z=-3<br> 6x+4y+9z=8<br> 11x-2y-z=7
Nutka1998 [239]

Answer:

thank you i need that

Step-by-step explanation:

4 0
3 years ago
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