One weights 30lbs the other weights 54lbs
Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
Answer:
X = 10
Step-by-step explanation:
if we say 1/2 base = <em>a</em>
a² = 13² - 12²
a² = 25
a = √25
a = 5
if 1/2 base = 5 then x = a × 2
hence X = 5 × 2 = 10
Answer:
The equation of the line is -4x + y = 3
Step-by-step explanation:
Since we have the slope, we can use it and either point in point-slope form and solve for the standard form of the equation.
y - y1 = m(x - x1)
y - -1 = 4(x - -1)
y + 1 = 4(x + 1)
y + 1 = 4x + 4
-4x + y + 1 = 4
-4x + y = 3
