given that an aluminum ore contains 25% bauxite Al(OH)3, how much aluminum would a 200g sample of ore contain?

How many moles are there in 45.0 grams of sulfuric acid,<br> H2SO4?

olga2289 [7]

Answer:

the answer is 0.4588162459

Explanation:

1 mole = 0.010195916576195

= 45 ×"

5 0

3 years ago

A cell is classified as eukaryotic if the cell

son4ous [18]

Answer:

contains a nucleus.

Explanation:

:)

5 0

3 years ago

How many moles of gold are Cleveland to 1.204×1024 atoms

Whitepunk [10]

Answer:

10

Explanation:

ye

4 0

3 years ago

A flask at room temperature contains exactly equal amounts (in moles) of nitrogen and xenon.

zalisa [80]

Answer:

a) Same

b) Nitrogen

c) Same

d) Nitrogen

Explanation:

a)

The formula for partial pressure of a gas is equal to

$p_B = n_B \frac{RT}{V}$

Here nB is the number of moles .

The number of moles for both the gases are same and hence the partial pressure for the two gases will also be same.

b) The greater average velocity is calculated by using following formula

$v_{RMS} = \sqrt{3RTM}$

Here M is the molar mass.

Molar mass of nitrogen is greater than the molar mass of xenon and hence nitrogen will have higher greater average velocity

c) As we know, the average kinetic energy of gas particles is dependent on the absolute temperature of gas and if all the gases are at same temperature, their kinetic energy will also be same. Since nitrogen and xenon are at same temperature, their kinetic energy will be same

d) Effusivity is depended directly on the thermal conductivity, density and and the specific heat capacity.

All these three parameters are higher in case of nitrogen. Thus, it will effuse first

4 0

3 years ago

Ne, c4h10, is a component of natural gas that is used as fuel for cigarette lighters. the balanced equation of the complete comb

Simora [160]

<span>3.68 liters First, determine the number of moles of butane you have. Start with the atomic weights of the involved elements: Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight oxygen = 15.999 Molar mass butane = 4*12.0107 + 10*1.00794 = 58.1222 g/mol Moles butane = 2.20 g / 58.1222 g/mol = 0.037851286 Looking at the balanced equation for the reaction which is 2 C4H10(g)+13 O2(g)â†’8 CO2(g)+10 H2O(l) It indicates that for every 2 moles of butane used, 8 moles of carbon dioxide is produced. Simplified, for each mole of butane, 4 moles of CO2 are produced. So let's calculate how many moles of CO2 we have: 0.037851286 mol * 4 = 0.151405143 mol The ideal gas law is PV = nRT where P = Pressure V = Volume n = number of moles R = Ideal gas constant ( 0.082057338 L*atm/(K*mol) ) T = absolute temperature (23C + 273.15K = 296.15K) So let's solve the formula for V and the calculate using known values: PV = nRT V = nRT/P V = (0.151405143 mol) (0.082057338 L*atm/(K*mol))(296.15K)/(1 atm) V = (3.679338871 L*atm)/(1 atm) V = 3.679338871 L So the volume of CO2 produced will occupy 3.68 liters.</span>

4 0

3 years ago