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3 years ago

Which represents the correst equilibrium constant expression for Cu(s) +2Ag<------> Cu^2 (aq) +2Ag(s)

Chemistry

1 answer:

nataly862011 [7]3 years ago

7 0

Answer:

$Kc=\frac{(Cu2)(Ag)^2}{(cu)(Ag)^2}$

Explanation:

because it is products / reactants

Hope this helps:)

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If they travel 75 meters in 10 seconds, how many meters must they travel each second?

kobusy [5.1K]

Answer:

Step-by-step explanation: We are asked to find the distance covered by a man in 15 minutes at a speed of 16 km/hr. 15 minutes = 15/60 hour. Therefore, the person can run 4 km in 15 minutes.

Explanation:

4 0

3 years ago

Mr. Chem S. Tree added water to 250. ML of a 2.50 M NaOH solution, until the final volume was 500. ML. What is the new molarity

tresset_1 [31]

Answer:

molarity of diluted solution = 1.25 M

Explanation:

Using,

C1V1 (Stock solution) = C2V2 (dilute solution)

given that

C1 = 2.50M

V1 = 250ML

C2 = ?

V2 = 500ML

2.50 M x 250 mL = C2 x 500 mL

C2 = (2.50 M x 250 mL) / 500 mL

C2 = 1.25 M

Hence, molarity of diluted solution = 1.25 M

4 0

3 years ago

Which is the correct formula for the compound made when aqueous solutions containing a dissolved magnesium compound and a dissol

jenyasd209 [6]

It would be MgCl₂ ~ Magnesium Chloride.

4 0

4 years ago

Read 2 more answers

Water is capable of dissolving a variety of different substances, which is why it is such a good solvent. It is often called the

Serggg [28]

Answer:

Explanation:

In this case the answer would be

Water is a polar molecule with positive and negative side

Now since these negative and positives are present in the water molecule . In easy terms when a substance reacts with water .the negative part of water ( oxygen ) reacts with the positive part of the substance and the positive part of the water ( hydrogen) reacts with negative part of the substance .if you look at the reason . Water is held up by one of the strongest attraction forces available .since most substances have weaker attraction forces between them ,therefore water can easily overcome them with its forces. Thus giving it the ability to dissolve a variety of substances

6 0

3 years ago

A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.

irga5000 [103]

Answer:

1. pH = 1.23.

2. $H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)$

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

$H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+$

It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:

$pH=pKa+log(\frac{[base]}{[acid]} )$

Whereas the pKa is:

$pKa=-log(Ka)=-log(5.90x10^{-2})=1.23$

The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:

$pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23$

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

$n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol$

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

$H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)$

Which is also shown in net ionic notation.

Best regards!

4 0

3 years ago