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vredina [299]
3 years ago
7

This question deals with waste disposal in the Solutions and Spectroscopy experiment. What should be done to waste solutions con

taining copper ion? (Select all that apply.) a. It should be flushed down the sink. b. It should be dumped in a beaker labeled "waste copper" on one's bench during the experiment. c. No waste will be generated in this experiment. d. It should be disposed of in the bottle for waste copper ion when work is completed. e. It should be returned to the bottle containing 0.5 M copper sulfate solution.
Chemistry
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

b. It should be dumped in a beaker labeled "waste copper" on one's bench during the experiment.

d. It should be disposed of in the bottle for waste copper ion when work is completed.

Explanation:

Solutions containing copper ion should never be disposed of by dumping them in a sink or in common trash cans, because this will cause pollution in rivers, lakes and seas, being a contaminating agent to both human beings and animals. They should be placed in appropriate compatible containers that can be hermetically sealed. The sealed containers must be labeled with the name and class of hazardous substance they contain and the date they were generated.

It never should be returned to the bottle containing the solution, since it can contaminate the solution of the bottle.

In the Solutions and Spectroscopy experiments there is always wastes.

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A wooden block has a volume of 25.3 cm3. Its mass is 17.0g. What is the density of this block?
kolbaska11 [484]
Density = (mass) / (volume)

Density = (17.0 g) / (25.3 cm³) = 0.672 gm per cm³. (rounded)
6 0
3 years ago
A 1.8 g sample of octane C8H18 was burned in a bomb calorimeter and the temperature of 100 g of water increased from 21.36 C to
melomori [17]

Answer:

HEAT OF COMBUSTION PER GRAM OF OCTANE IS 1723.08 J OR 1.72 KJ/G OF HEAT

HEAT OFF COMBUSTION PER MOLE OF OCTANE IS 196.4 KJ/ MOL OF HEAT

Explanation:

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

In other words, 3101.56 J of heat was evolved from the reaction of 1.8 g octane with water.

Heat of combustion of octane per gram:

1.8 g of octane produces 3101.56 J of heat

1 g of octane will produce ( 3101.56 * 1 / 1.8)

= 1723.08 J of heat

So, heat of combustion of octane per gram is 1723.08 J

Heat of combustion per mole:

1.8 g of octane produces 3101.56 J of heat

1 mole of octane will produce X J of heat

1 mole of octane = 114 g/ mol of octane

So we have:

1.8 g of octane = 3101.56 J

114 g of octane = (3101.56 * 114 / 1.8) J of heat

= 196 432.13 J

= 196. 4 kJ of heat

The heat of combustion of octane per mole is 196.4 kJ /mol.

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

8 0
3 years ago
Hydrogen peroxide decomposes to form water and oxygen gas according to the following equation: 2H2O2(aq)  2H2O(l) + O2(g) If 31
olya-2409 [2.1K]

Answer:

141.89 dm^3

Explanation:

The equation of the reaction is;

2H2O2(aq) --------->2H2O(l) + O2(g)

Now , we are told that the mass of hydrogen peroxide decomposed was 315g. Number of moles of hydrogen peroxide in 315g of the substance is given by;

Number of moles= mass/molar mass

Molar mass of hydrogen peroxide= 34.0147 g/mol

Number of moles= 315g/34.0147 g/mol = 9.26 moles of hydrogen hydrogen peroxide.

From the reaction equation;

2 moles of hydrogen peroxide yields 1 mole of oxygen

9.26 moles of hydrogen peroxide yields 9.26 ×1/2 = 4.63 moles of oxygen

From the ideal gas equation;

Volume of the gas V= the unknown

Pressure of the gas P= 0.792 atm

Temperature of the gas= 23°C +273 = 296 K

Number of moles of oxygen = 4.63 moles of oxygen

R= 0.082atmdm^3K-1mol-1

Hence, from PV=nRT

V= nRT/P

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8 0
4 years ago
Difference between fluids and nonfluids
Mamont248 [21]

Answer:

All liquids are fluids but not all fluids are liquids. Fluids basically describe anything that can flow as a result of a difference in pressure between two points. Liquids on the other hand are a subset of fluids. Liquids are the incompressible fluids. These are the fluids who's density does not change sharply with pressure.

Gases are also fluids, they form the compressible fluids. They do flow as a result of difference in pressure between two points but at the same time they can be compressed or expanded. Their density fluctuates with pressure.

Hence fluids consist of 2 mutually exclusive groups of compressible and incompressible fluids. Liquids are the incompressible fluids and hence form a subset of the more general term fluid.

5 0
3 years ago
You are a scientist working on increasing the efficiency of appliances to waste less electricity. You are running experiments me
bezimeni [28]
Answer : Option A) 45.5%
 
Explanation : We use the formula of calculating energy efficiency which is as,

η (in %)= [P_{Out} / P_{in}] X 100 
where η is energy efficiency,
and P values are for energy out and in.

So plugging the given values, we get,

η (in %) = (11825.5 / 25978.8) X 100 = 45.5 %
5 0
3 years ago
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