Simplify 76 ⋅ 75. (4 points) 4911 4935 711 735
2 answers:
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Answer:
The calculated chi -square value =5.7356 Is less than12.01 at 0.1level of significance .
The null hypothesis is accepted.
The past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.
Step-by-step explanation:
<u>Step:-(1)</u>
Given data 28 25 29 25 32 36 27 24
Sample size 'n' = 8
mean of the sample (x⁻) = ∑x /n =
mean of the sample (x⁻) = 28.25
x x- x⁻ (x-x⁻ )²
28 28 - 28.25 = -0.25 0.0625
25 25 -28.25 = -3.25 10.56
29 29-28.25 = 0.75 0.5625
25 25-28.25 = -3.25 10.56
32 32-28.25 = 3.75 14.06
36 36-28.25 = 7.75 60.06
27 27-28.25 = -1.25 1.5625
24 24-28.25 = -4.25 18.06
∑(x-x⁻)² = 115.4875
<u>Step:-(2)</u>
The sample standard deviation
S² = ∑(x-x⁻)²/n-1 = = 16.49
By using χ² distribution
χ² =
By above test can be applied only if the population from which sample is drawn normal.
Given data For the past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.
Population variance σ² = 23
<u>Step:-(3)</u>
Null hypothesis :H₀:σ² = 23
Alternative hypothesis :H₁:≠23
<u>The calculated chi -square value =5.7356</u>
The degrees of freedom γ=n-1 =8-1=7
The tabulated value of chi -square = 12.01 at 0.1level of significance (check table)
The calculated chi -square value =5.7356 Is less than12.01 at 0.1level of significance .
The null hypothesis is accepted.
<u>Conclusion</u>:-
The null hypothesis is accepted.
The past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.
The first step is to draw the graph. Once we do this, we can easily see that the vertex is at (12,64), which means that the hourly profit of coffee sold is highest at 12 cups of coffee. The x-intercepts are at x = 4 and x = 20, which means that between 0 and 4 (inclusive) cups of coffee sold, and after 20 cups sold, there is no profit.
