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Vesna [10]
3 years ago
8

Consider a river flowing toward a lake at an average speed of 3m/s at a rate of 500 m^3/s at a location 58m above the lake surfa

ce. Determine the total mechanical energy of the river water per unit mass (in kJ/kg) and the power generation potential of the entire river at that location (in MW). The density of water is 1000 kg/m^3, and the acceleration due to gravity is 9.81 m/s^2.
Physics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

Total power generation will be 291.465 MW

Explanation:

We have given that river is flowing at rate of  V = 500m^3/sec

Average speed v = 3 m/sec

Height h = 58 m

We know that total mechanical energy is given by

E = KE +PE

E=\frac{1}{2}mv^2+mgh

Energy per unit mass

\frac{E}{m}=\frac{1}{2}v^2+gh=\frac{1}{2}\times 3^2+9.81\times 58=583.29j/kg

Total power generation from the river is given by

P=energy\ per\ unit\ mass\times volume\ flow\ rate\times density

So P=583.29\times 500\times 1000=291.465MW

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Answer:

Where are the images?

Explanation:

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A baseball pitcher loosens up his pitching arm. He tosses a 0.20-kg ball using only the rotation of his forearm, 0.28 m in lengt
gayaneshka [121]

Answer:

Moment of Inertia, I = 0.016 kgm²

Explanation:

Mass of the ball, m = 0.20 kg

Length of the pitcher's arm, l = 0.28

Radius of the circular arc, r = 0.28 m

Moment of Inertia is given by the formula:

I = mr²

I = 0.20 * 0.28²

I = 0.20 * 0.0784

I = 0.01568

I = 0.016 kgm²

5 0
4 years ago
Electrons of wavelength 1.5 nm are emitted from a material when light of wavelength 350nm is incident on it. What is the work fu
krok68 [10]

Answer:

3.5434 eV

Explanation:

For a particle with kinetic energy E and mass m , the wavelength  associated is given by the following relation,

\lambda=\frac{h}{\sqrt{2mE} }

E = \frac{h^2}{2m\lambda^2}

Putting the values  we get

E = \frac{(6.6\times(10^{-34})^2}{2\times9.1\times10^{-31\times(1.5\times10^{-9})^2}}

=1.063 x 10⁻²¹ J

= .0066 eV.

Energy of¹light in terms of eV

= 1244 / 350 = 3.55 eV.

Work function = 3.55 - 0.0066 = 3.5434 eV.

7 0
4 years ago
1. When does raising the temperature of a gas increase its pressure? when volume is increased and the number of particles is con
Neporo4naja [7]

Answer:

when volume and the number of particles are constant

Explanation:

Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

PT = K

\frac{P1}{T1} = \frac{P_{2}}{T_{2}}

The ideal gas law is the equation PV = nRT

Where;

P is the pressure.

V is the volume.

n is the number of moles of substance.

R is the ideal gas constant.

T is the temperature.

Generally, raising the temperature of an ideal gas would increase its pressure when volume and the number of particles are constant.

This ultimately implies that, when volume and the number of particles are held constant, there would be a linear relationship between the temperature and pressure of a gas i.e temperature would be directly proportional to the pressure of the gas. Thus, an increase in the temperature of the gas would cause an increase in the pressure of the gas at constant volume and number of particles.

3 0
3 years ago
Consider an elevator carrying Kermit the frog weighing 4000.0 N is held 5.00 m above a spring with a force constant of
tigry1 [53]

Answer:

The maximum compression distance of the spring is 0.375 m

Explanation:

The given parameters are;

The weight of the elevator and the frog = 4,000.0 N

The location of the elevator above the spring = 5.00 m

The force constant of the spring, k = 8,000.0 N/m

The frictional force of the brakes = 1,000.0 N

The net force, F, of the elevator on the spring is F = 4,000.0 N - 1,000.0 N = 3,000.0 N

F = 3,000.0 N

The maximum compression distance of the spring, x is given as follows;

F = k × x

Substituting the known values gives;

3,000.0 N = 8,000.0 N/m × x

∴ x = (3,000.0 N)/(8,000.0 N/m) = 0.375 m

x = 0.375 m = 37.5 cm

The maximum compression distance of the spring, x = 0.375 m.

4 0
3 years ago
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