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klemol [59]
3 years ago
8

If to cars A and B started at the same position, which car would have won the race, and explain why

Physics
2 answers:
kozerog [31]3 years ago
8 0
They would have tied, because they started at the same place. 
valentina_108 [34]3 years ago
7 0
We have no way to tell. We know nothing about the race except the names of the cars.
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Suppose you have a car with a battery that applies 12.5 V to the starter.
Marat540 [252]

Answer:

R = 0.1 ohms

Explanation:

It is given that,

Voltage of the battery, V = 12.5 V

Current flowing in the car's starter, I = 125 A

We need to find the effective resistance of a car's starter. It can be calculated using Ohm's law. Let R is the resistance.

V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{12.5}{125}\\\\R=0.1\ \Omega

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3 years ago
"if the left-hand mass is 2.3 kg ,what should the right-hand mass be so that it accelerates downslope at 0.64 m/s2?"
VARVARA [1.3K]

m₁ = 2.3 kg <span>
θ₁ = 70° </span><span>
θ₂ = 17° </span><span>
g = 9.8 m/s² 

->The component of the gravitational force on m₁ that is parallel down the incline is: </span><span>
F₁ = m₁ × g × sin(θ₁) </span><span>
F₁ = (2.3 kg) × (9.8 m/s²) × sin(70°) = 21.18 N </span><span>

->The component of the gravitational force on m₂ that is parallel down the incline is: </span><span>
F₂ = m₂ × g × sin(θ₂) </span><span>
F₂ = m₂ × (9.8 m/s²) × sin(70°) = m₂ × (2.86 m/s²) </span><span>

Then the total mass of the system is: 
m = m₁ + m₂ </span><span>
m = (2.3 kg) + m₂ </span><span>

If it is given that m₂ slides down the incline, then F₂ must be bigger than F₁, </span><span>
and so the net force on the system must be: 
F = m₂×(2.86 m/s²) - (21.18 N) </span><span>

Using Newton's second law, we know that 
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So if we want the acceleration to be 0.64 m/s², then 
m₂×(2.86 m/s²) - (21.18 N) = [(2.3 kg) + m₂] × (0.64 m/s²) </span><span>
m₂×(2.86 m/s²) - (21.18 N) = (1.47 N) + m₂×(0.64 m/s²) </span><span>
m₂×(2.22 m/s²) = (22.65 N) </span><span>
m₂<span> = 10.2 kg</span></span>

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